Polar Coordinates: Solving for Angle in Second Quadrant | 59.1 Degrees

[chocolatelover]

Homework Statement

The angle is 59.1, which is in the second quadrant. Give the angle from the positive x-axis.

Homework Equations

The Attempt at a Solution

180-59.1=120.9

Does that look right?

Thank you very much

 

[rocomath]

The angle is 59.1, which is in the second quadrant. Give the angle from the positive x-axis.

Quadrant one is from 0 to 90 degrees. Quadrant two is 90 to 180.

 

[chocolatelover]

Thank you very much

Do you see where I went wrong?

A vector has an x component of -24.5 unites and a y component of 41.0 units. Find the magnitude and direction of this vector (from the positive x-axis)

I got 47.8 by doing (41.0)^2 + (-24.5)^2=c^2
c=47.8 units

In order to find the magnitude I did sin(theta)=41.0/47.8
=59.1 I need the magnitude from the positive x-axis. Would I then take 180-59.1?

Thank you