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Polarization of photon-Peskin and Schroeder

  1. Apr 19, 2013 #1

    ndcat10

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    Hi, I am currently studying quantum field theory with worldwidely used text written by Peskin and Schroeder. On page 165 of that text it says, " the amplitude vanishes unless the final photon is right-handed." But I cannot figure out how it works. With ε = (0,1,i,0), I get same expression located right after 5.100, which result in 0 when it applies to [itex] u_R = \pmatrix{ 0 \cr 1} [/itex]. I think there must be something related to photon polarization and I am missing. Could you find where I got wrong? Thanks in advance.
     
    ndcat10, Apr 19, 2013
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  3. Apr 19, 2013 #2

    copernicus1

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    I'm not sure if this is the issue you're having since I don't have my book in front of me, but I know they use a different convention than most on the Jones vectors. Usually, right polarized is (0,1,-i,0). Maybe this would make a difference?

    http://en.wikipedia.org/wiki/Jones_vector#Jones_vectors
     
    copernicus1, Apr 19, 2013
  4. Apr 19, 2013 #3

    ndcat10

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    I still cannot figure out the connection between Jones vectors and my problem. Anyway thanks a lot :)
     
    ndcat10, Apr 19, 2013
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