Polarizing Light through Two Filters

  • Thread starter Thread starter thiefjack
  • Start date Start date
  • Tags Tags
    Filters Light
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 2K views
thiefjack
Messages
11
Reaction score
0
Hello, all.

I have a general question related to something I read in a book right now. Not taking a course so I have no professor to ask, so I come to you all!

To speed things up, I have this image I took from the book:
xlvMtdrl.png


My question is if the analyzer's polarizing axis was an arbitrary theta from the vertical, then E perpendicular would still lie on it's axis, right? As long as it wasn't perpendicular.

I'm having a hard time visualizing this for some reason.
 
Physics news on Phys.org
E perpendicular is by definition taken perpendicularly to the analyzer's axis, no matter how the latter axis is oriented.
 
Say the analyzer's axis is at angle θ where θ is measured clockwise from the vertical, same as with phi, the polarizer axis angle. Then the electric field vector at the analyzer output would be oriented as θ with magnitude cos(θ - phi). In your illustration, θ = 0.