Pole of a function, as a geometric series

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cragar
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Homework Statement


Determine the order of the poles for the given function.
[itex]f(z)=\frac{1}{1+e^z}[/itex]

Homework Equations

The Attempt at a Solution


I know if you set the denominator equal to zero
you get z=ln(-1)
But if you expand the function as a geometric series ,
[itex]1-e^{z}+e^{2z}...[/itex]
I don't see how there is a pole in the geometric series expansion , there is no division by zero. [/B]
 
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