Police Car Overtaking Speeder: How to Calculate the Time and Distance?

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Homework Statement



A police ar traveling a constant 90 km/h is passed by a speeder travelig 130 km/h. 1.00s after the speeder passes, the policeman steps on the accelerator. If the police car's acceleration is 2.00 m/s^2, how much time elapses after the police car is passed until it overtakes the speeder (assumed moving at a constant speed)



The Attempt at a Solution


This is my first encounter with these types of problems, at the level where I need to solve it without trial and error graphing.

Could someone provide a bit of guidance because I'm not sure how to do this problem.
 
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What is the position of the speeder at time t.
What is the position of the policeman at time t.
for what t are they equal.

motion with constant acceleration:
[tex]x = x_0 + v_0 t + (1/2) a t^2[/tex]

motion with constant velocity
[tex]x = x_0 + v_0 t[/tex]