The problem involves a scenario where an unmarked police car, initially traveling at a constant speed, is passed by a speeder. The police car accelerates after a brief delay, and the discussion centers on determining the time it takes for the police car to overtake the speeder, who is moving at a constant speed. The subject area relates to kinematics and motion equations.
The discussion is active, with participants offering guidance on how to set up the problem and create equations for each vehicle's motion. There is a recognition of the need to account for the initial delay of the police car. However, some participants express frustration and seek more direct assistance in navigating the problem.
Participants note that this is a non-calculus based course, which may influence the methods and equations discussed. There is also a sense of urgency due to impending deadlines for the homework.
Do a distance - time graph for each of the vehicles. What is the relationship between the co-ordinates (distance and time) of the two cars when the police car overtakes the speeder?iffanytay said:An unmarked police car, traveling a constant 87.0km/hr, is passed by a speeder traveling 134km/hr. Precisely 1.11s after the speeder passes, the policeman steps on the accelerator. If the police car's acceleration is 1.94m/s2, how much time elapses after the police car is passed until it overtakes the speeder (assumed moving at constant speed)?
anything!
iffanytay said:An unmarked police car, traveling a constant 87.0km/hr, is passed by a speeder traveling 134km/hr. Precisely 1.11s after the speeder passes, the policeman steps on the accelerator. If the police car's acceleration is 1.94m/s2, how much time elapses after the police car is passed until it overtakes the speeder (assumed moving at constant speed)?
anything!
iffanytay said:thank you ill try that. does anyone know how to do it using the x=xo+volt+1/2at^2 equation?
iffanytay said:I already converted and I've set the individual problems up for each car so many times but somehow i just get lost. I don't know what to do once i get to that point.
iffanytay said:if anyone has the answer please can i have it. i keep getting so lost when i try to set the equations equal to each other and it is due really soon.