An unmarked police car traveling a constant 80km/h is passed by a speeder traveling 135km/h.
Precisely 3.00s after the speeder passes, the police officer steps on the accelerator; if the police car's acceleration is 1.50m/s2 , how much time passes before the police car overtakes the speeder after the speeder passes (assumed moving at constant speed)?
~I would sincerely appreciate help with this question. It's the only problem I'm having a difficult time understanding.
The attempt at a solution
I keep getting stuck at: 37.5t = 66.66 +22.22t - 66.66 + 1/2a(t-3)^2
Not sure if I'm even approaching it right.