Polynomial Functions w/ zeros.

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SUMMARY

The polynomial function with the specified zeros of 2, 4+sqrt(5), and 4-sqrt(5) can be expressed as y=(x-2)((x-4)+sqrt(5))((x-4)-sqrt(5)). This simplifies to the monic polynomial of lowest degree: y = x^2 - 8x + 11. The discussion emphasizes that there are infinitely many polynomial functions that can have these zeros, highlighting the flexibility in polynomial representation.

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AznBoi
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Ok I have a probelm with find the polynoimal function which has these zeros:

Zeros: 2, 4+sqrt.(5), 4-sqrt.(5)

Find the polynomial equation with the given zeros.

So far I know:

y=(x-2)(x-(4+sqrt.(5))(x-(4-sqrt.(5))

but is there any way I could make the factor (x-(4+sqrt.(5)) into a better one? For example:

Zeros: -2,-1,0,1,2

I did:
y=x(x^2-1)(x^2-4)

instead of y=x(x+2)(x+1)(x-1)(x-2)

Thanks! :biggrin:
 
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AznBoi said:
Ok I have a probelm with find the polynoimal function which has these zeros:
Zeros: 2, 4+sqrt.(5), 4-sqrt.(5)

Find the polynomial equation with the given zeros.
Not "the" polynomial function- "a" polynomial function. There are an infinite number of polynomial functions having these zeros.

So far I know:

y=(x-2)(x-(4+sqrt.(5))(x-(4-sqrt.(5))

but is there any way I could make the factor (x-(4+sqrt.(5)) into a better one?
Yes, much as you did with -2, 2, and -1, 1 below: [itex](x-(4+\sqrt{5}))(x- (4-\sqrt{5}))= ((x-4)+\sqrt{5})((x-4)-\sqrt{5})= (x-4)^2- 5[/itex]
[itex]= x^2- 8x+ 16- 5= x^2- 8x+ 11[/itex]
That is the monic polynomial of lowest degree having those roots.
For example:

Zeros: -2,-1,0,1,2

I did:
y=x(x^2-1)(x^2-4)

instead of y=x(x+2)(x+1)(x-1)(x-2)

Thanks! :biggrin:
 

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