Polynomial transformation of random variable

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Homework Help Overview

The discussion revolves around finding the distribution of a transformed random variable, specifically f(X) = X^2 + X, where X has a known distribution, such as a beta distribution. The challenge lies in applying transformation techniques to derive the new distribution.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss various methods for transformation, including the standard transformation theorem and conditioning. There are attempts to find the inverse of the function, with some expressing difficulty in doing so. Others suggest separating domains to address the non-invertibility of the function.

Discussion Status

Some participants have provided hints and references to relevant formulas, while others are exploring different approaches to the problem. There is an acknowledgment of the complexity involved, and multiple interpretations of the problem are being considered.

Contextual Notes

Participants note that the function f(X) is not invertible over the entire line, which complicates the transformation process. There is also a mention of the participants' varying levels of familiarity with probability concepts, indicating potential gaps in knowledge that may affect their approaches.

raynard
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Homework Statement



Given a random variable X with a known distribution (e.g. a beta distribution), find the distribution of
f(X) = X^2 + X

The Attempt at a Solution



I've tried the normal approaches: the standard transformation theorem; conditioning on X; Laplace transformation, etc. They don't seem to work. Any hints?
 
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Thanks for the reply!

I tried the standard method you described, but I see no easy way to find the inverse of

f: x -> x^2 + x
 
Yup, I don't think it's very pretty...
I have to say, I'm pretty rusty when it comes to probability. I remember the best ways to solve this type of questions is to write Y = X2 + X, and then:
P(Y < y) = P (X2 + X < y) = P(X2 + X - y < 0 ) = ...

Then you'd have to solve this inequality and proceed from there...
But maybe there are shortcuts. I just responded cause I saw no one else did :-)
 

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