Polytropic Process equation [Thermodynamics]

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SUMMARY

The discussion centers on the transformation of the polytropic process equation in thermodynamics, specifically from (1/(1-n))*(p1v1-p2v2) to (n/(n-1))*(p1v1-p2v2). This transformation is relevant in the context of the Rankine Cycle, which is a continuous flow process involving a turbine. The key distinction made is between open and closed systems, where in an ideal adiabatic open system, work correlates with the change in enthalpy, while in a closed system, it correlates with the change in internal energy. Understanding these concepts is crucial for grasping the implications of the Rankine Cycle.

PREREQUISITES
  • Understanding of polytropic processes in thermodynamics
  • Familiarity with the Rankine Cycle and its components
  • Knowledge of open vs. closed thermodynamic systems
  • Basic principles of enthalpy and internal energy
NEXT STEPS
  • Study the derivation of the polytropic process equation in detail
  • Explore the Rankine Cycle and its applications in power generation
  • Learn about the differences between open and closed system thermodynamics
  • Investigate the relationship between work, enthalpy, and internal energy in thermodynamic processes
USEFUL FOR

Students of thermodynamics, engineers working with power cycles, and anyone interested in the principles of energy conversion in open and closed systems.

nichmetsa
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TL;DR
(1/(1-n))*(p1v1-p2v2) into (n/(n-1))*(p1v1-p2v2)
Hello there,
So yesterday my thermodynamics professor did some black magic and transformed our beloved equation (1/(1-n))*(p1v1-p2v2) into (n/(n-1))*(p1v1-p2v2), but i didnt understand why he did it and how (he is too fast for my writing). Does anyone know how he did it, are there any restrictions to this formula? Just for context he was doing a introduction to the Rankine Cycle.
 
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The Rankine cycle is a continuous flow process involving a turbine (open system), rather than a bath process involving a piston and cylinder (closed system). In an ideal adiabatic open system process, the work is equal to the change in enthalpy, compared to a closed system, where the work is equal to the change in internal energy.
 

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