[Thermodynamics] Heat Capacity for Polytropic Process

  • #1
mef51
23
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Consider an ideal gas. For a polytropic process we have ##PV^n = const##. Different values of ##n## will represent different processes; for example isobaric (##n=0##), isothermal (##n=1##), and isochoric (##n=\infty##).

The Wikipedia article on polytropic processes states that the specific heat for a polytropic process is given by
##C_n = C_v \frac{\gamma - n}{1 - n}## where ##\gamma = \frac{C_P}{C_v}##

We can see that this expression for ##C_n## reduces to what we expect for the different values of n..
For example if ##n = 0## (isobaric) we have ##C_0 = C_v \frac{\gamma}{1} = C_v \frac{C_P}{C_v} = C_P##.

How is the equation ##C_n = C_v \frac{\gamma - n}{1 - n}## derived?
 
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  • #2
mef51 said:
Consider an ideal gas. For a polytropic process we have ##PV^n = const##. Different values of ##n## will represent different processes; for example isobaric (##n=0##), isothermal (##n=1##), and isochoric (##n=\infty##).

The Wikipedia article on polytropic processes states that the specific heat for a polytropic process is given by
##C_n = C_v \frac{\gamma - n}{1 - n}## where ##\gamma = \frac{C_P}{C_v}##

We can see that this expression for ##C_n## reduces to what we expect for the different values of n..
For example if ##n = 0## (isobaric) we have ##C_0 = C_v \frac{\gamma}{1} = C_v \frac{C_P}{C_v} = C_P##.

How is the equation ##C_n = C_v \frac{\gamma - n}{1 - n}## derived?
I can help you with the derivation of this equation. But, before I do, please confirm that this is not a homework problem (or re-introduce it in one of the homework forums).
 
  • #3
It's not a homework problem.
I had an attempt at it and this is what I got: (I used ##\alpha## as the polytropic index instead of ##n##)

Using: ##\delta Q = nC_\alpha dT## and ##dU = nC_vdT##
$$
\delta Q = dU + \delta W \\
nC_\alpha dT = nC_vdT + PdV \\
nC_\alpha \triangle T = nC_v\triangle T + \int \frac {PV^\alpha}{V^\alpha}dV \\
nC_\alpha \triangle T = nC_v\triangle T + PV^\alpha\int \frac {1}{V^\alpha}dV \\
nC_\alpha \triangle T = nC_v\triangle T + PV^\alpha\int \frac {1}{V^\alpha}dV \\
nC_\alpha \triangle T = nC_v\triangle T + PV^\alpha \frac{1}{-\alpha + 1}V^{-\alpha + 1} \\
nC_\alpha \triangle T = nC_v\triangle T + PV \frac{1}{-\alpha + 1} \\
C_\alpha = C_v + \frac{PV}{n\triangle T} \frac{1}{-\alpha + 1} \\
C_\alpha = C_v + \frac{R}{1 - \alpha} \\
$$
 
  • #4
It looks like you had the right idea, and your last equation is correct, but I'm not able to understand how you got to that point because of notational issues. For the work W, I got:

[tex]W=-\frac{P_iV_i}{(\alpha -1)}\left[\left(\frac{V_i}{V_f}\right)^{\alpha -1}-1\right]=-\frac{nRT_i}{(\alpha -1)}\left[\left(\frac{V_i}{V_f}\right)^{\alpha -1}-1\right][/tex]

Also, by combining the ideal gas law with the polytropic equation, I get:

[tex]\left(\frac{V_i}{V_f}\right)^{\alpha -1}=\frac{T_f}{T_i}[/tex]

Combining these two equations, I get:
[tex]W=-\frac{nR}{(\alpha -1)}(T_f-T_i)[/tex]

Substituting this into the first law gives:

[tex]nC_{\alpha}\Delta T=nC_v\Delta T-\frac{nR\Delta T}{\alpha -1}[/tex]

Cancel the n and the delta T from both sides, reduce the right hand side to a common denominator, and factor the Cv from the right side, and you obtain the desired relationship.

Chet
 
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