Porential across current source

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Altairs
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Homework Statement


Title says it all. Question is attached.

Homework Equations



Simple KCLs, KVLs etc

The Attempt at a Solution



What I don't get is that isn't [tex]I_{R_{4}} = \frac{R_{3}}{R_{3}+R_{4}} * I1[/tex]
 
Attachments
  • Circuit schematic with resistors R6 (5R), R5 (60R), R3 (10R), R4 (30R), R1 (30R), R2 (10R) and R7 (10R) plus a current source I1 rated 0.8A between a middle node and the right node.
    circuit.JPG
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Altairs said:

Homework Statement


Title says it all. Question is attached.

Homework Equations



Simple KCLs, KVLs etc

The Attempt at a Solution



What I don't get is that isn't [tex]I_{R_{4}} = \frac{R_{3}}{R_{3}+R_{4}} * I1[/tex]

This expression is for a current divider. It would be valid if R3 and R4 were in parallel, which they are not.
Write Kirchoff's equations for the 3 loops to obtain the voltages on the terminals of R4 and R2. The voltage on the source is the difference between them.