Porential across current source

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SUMMARY

The discussion focuses on analyzing a circuit problem involving current division and Kirchhoff's laws. The user incorrectly applies the current divider formula I_{R_{4}} = \frac{R_{3}}{R_{3}+R_{4}} * I1, which is only valid for resistors in parallel. The correct approach involves writing Kirchhoff's Voltage Laws (KVL) for the three loops in the circuit to determine the voltages across resistors R4 and R2. This method will yield the accurate voltage difference across the source.

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  • Understanding of Kirchhoff's Current Law (KCL)
  • Familiarity with Kirchhoff's Voltage Law (KVL)
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Altairs
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Homework Statement


Title says it all. Question is attached.

Homework Equations



Simple KCLs, KVLs etc

The Attempt at a Solution



What I don't get is that isn't [tex]I_{R_{4}} = \frac{R_{3}}{R_{3}+R_{4}} * I1[/tex]
 

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Altairs said:

Homework Statement


Title says it all. Question is attached.

Homework Equations



Simple KCLs, KVLs etc

The Attempt at a Solution



What I don't get is that isn't [tex]I_{R_{4}} = \frac{R_{3}}{R_{3}+R_{4}} * I1[/tex]

This expression is for a current divider. It would be valid if R3 and R4 were in parallel, which they are not.
Write Kirchoff's equations for the 3 loops to obtain the voltages on the terminals of R4 and R2. The voltage on the source is the difference between them.
 

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