1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Position/acceleration derivatives problem

  1. Apr 1, 2013 #1
    1. The problem statement, all variables and given/known data

    An object is traveling along a linear path according to the equation s(t) = 4t^3 - 3t^2 + 5 where t is measured in seconds and s(t) measured in meters. How far has the object traveled when its acceleration is zero?

    2. Relevant equations



    3. The attempt at a solution

    The acceleration time function is (or second derivative of position) is, a(t)= 24t-6.
    Then since a(t)=0, t=1/4 s.
    And know we take the difference between s(1/4) and s(0), since the object initially starts 5m to the right of the origin at t=0s.
    So, d=s(1/4)-s(0)
    =-1/8m
    Is this correct?
     
  2. jcsd
  3. Apr 1, 2013 #2

    HallsofIvy

    User Avatar
    Staff Emeritus
    Science Advisor

    Yes, that is well done.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Position/acceleration derivatives problem
Loading...