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Homework Help: Position/acceleration derivatives problem

  1. Apr 1, 2013 #1
    1. The problem statement, all variables and given/known data

    An object is traveling along a linear path according to the equation s(t) = 4t^3 - 3t^2 + 5 where t is measured in seconds and s(t) measured in meters. How far has the object traveled when its acceleration is zero?

    2. Relevant equations

    3. The attempt at a solution

    The acceleration time function is (or second derivative of position) is, a(t)= 24t-6.
    Then since a(t)=0, t=1/4 s.
    And know we take the difference between s(1/4) and s(0), since the object initially starts 5m to the right of the origin at t=0s.
    So, d=s(1/4)-s(0)
    Is this correct?
  2. jcsd
  3. Apr 1, 2013 #2


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    Science Advisor

    Yes, that is well done.
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