(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

A squirrel has x and y coordinates (1.1m, 3.4m) at time t_{1}=0.0s and coordinates (5.3m, -0.5m) at time t_{2}=3.0s. For this time interval, find (a) the components of the average velocity, and (b) the magnitude and direction of the average velocity.

2. Relevant equations

v_{avg}=[tex]\Delta[/tex]x/[tex]\Delta[/tex]t.

3. The attempt at a solution

X_{v avg}= (5.3m - 1.1m)/(3.0s - 0.0s) = 1.4 m/s

Y_{v avg}= (-0.5m - 3.5m)/(3.0s - 0.0s) = -1.3 m/s

I know these values are correct because I checked them in the back of the book. I don't understand how they get the magnitude and direction of the average velocity.

http://img704.imageshack.us/img704/8484/20240551.png [Broken]

Here's a picture of the average velocity vectors. The resultant vector (the diagonal line) should be [tex] \sqrt{(-1.3 m/s)^2+(1.4m/s)^2}[/tex], which is 0.52 m/s. The book says it's 1.9 m/s, which means they made Y_{v avg}a positive 1.3 m/s. Why did they do this?

**Physics Forums | Science Articles, Homework Help, Discussion**

Dismiss Notice

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Homework Help: Position and velocity vectors of a squirrel

**Physics Forums | Science Articles, Homework Help, Discussion**