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Position of an oscillating object

  1. Nov 9, 2016 #1
    1. The problem statement, all variables and given/known data

    The position of an object that is oscillating on an ideal spring is given by the equation x =
    (12.3 cm) cos[(1.26s-1)t]. At time t = 0.815 s,
    (a) how fast is the object moving?
    (b) what is the magnitude of the acceleration of the object?

    2. Relevant equations
    As follow
    3. The attempt at a solution
    dx/dt = -12.3*(1.26)sin(1.26*.815) = -0.2777 cm/s but the answer is -13.3cm/sec
    dx^2/dt^2= -12.3*(1.26)^2*cos(1.26*.815) = -19.524 cm/s^2 but the answer is -10.1cm/sec^2

    I have only little time before test.hope there is someone help me soon.tell me whats wrong with it.
    (Please don't ask me to guess... i m not good at that and i really have not time left...)
    Thank you very much for helping me
     
  2. jcsd
  3. Nov 9, 2016 #2

    vela

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    ##12.3 \ne 1.23## for one thing.
     
  4. Nov 9, 2016 #3
    Thanks for reminding
    Thats only multiple of 10, still canet get the answer
    Also, the calculated answer is not affect by this typo
    Sorry for typo
     
  5. Nov 9, 2016 #4

    vela

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    Make sure your calculator is in radian mode.
     
  6. Nov 9, 2016 #5
    Ahhh yes
    Thanksssssss
     
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