Position, velocity, and acceleration vectors

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SUMMARY

The discussion focuses on calculating total vector displacement, average speed, and average velocity for a motorist's trip involving multiple directional movements. The motorist travels south at 20 m/s for 3 minutes, west at 25 m/s for 2 minutes, and northwest at 30 m/s for 1 minute. Key calculations include converting time to seconds and understanding that displacement is a vector quantity, which differs from distance. The average speed is determined to be 23.3 m/s, while average velocity requires the total displacement divided by the total time of 360 seconds.

PREREQUISITES
  • Understanding of vector quantities and their properties
  • Knowledge of basic kinematics equations, specifically Vs = d/delta t and Vave = delta x/delta t
  • Ability to convert time units from minutes to seconds
  • Familiarity with directional movement in a Cartesian coordinate system
NEXT STEPS
  • Calculate total vector displacement using trigonometric functions for the northwest direction
  • Learn about vector addition to combine displacement vectors accurately
  • Explore the concept of average velocity in different motion scenarios
  • Study the differences between scalar and vector quantities in physics
USEFUL FOR

Students studying physics, particularly those focusing on kinematics, as well as educators looking for examples of vector displacement and average velocity calculations.

riafran
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Homework Statement



A motorist drives south at 20m/s for 3min, then turns west and travels at 25m/s for 2min, and finally travels northwest at 30m/s for 1min. For this 6min trip, find:
a) the total vector displacement
b) the average speed
c) average velocity

let the positive x-axis point east


Homework Equations



Vs = d/delta t
Vave= delta x/delta t



The Attempt at a Solution



i converted the mins to seconds, getting

south = 3600m
west = 3000m
northwest = 1800m

im getting confused because displacement is not the same as distance so i can't just add all 3 values together

for average speed i for 8400/6min = 23.3m/s

and I am not sure how to find the change in x for average velocity..

please help! thank you! =]
 
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riafran said:

Homework Statement



A motorist drives south at 20m/s for 3min, then turns west and travels at 25m/s for 2min, and finally travels northwest at 30m/s for 1min. For this 6min trip, find:
a) the total vector displacement
b) the average speed
c) average velocity

let the positive x-axis point east

Homework Equations



Vs = d/delta t
Vave= delta x/delta t

The Attempt at a Solution



i converted the mins to seconds, getting

south = 3600m
west = 3000m
northwest = 1800m

im getting confused because displacement is not the same as distance so i can't just add all 3 values together

for average speed i for 8400/6min = 23.3m/s

and I am not sure how to find the change in x for average velocity..

please help! thank you! =]

You found the speed. But Velocity is a vector. So is displacement.
Its magnitude is Displacement divided by the scalar Time.
So the average for the trip will be the total displacement divided by 360s.
 

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