Position when 2 objects pass each other

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Homework Help Overview

The problem involves two objects: one thrown downward from a height of 99 m with an initial speed of 4 m/s, and another propelled upward from ground level with a speed of 25 m/s. The goal is to determine the height at which the two objects pass each other, considering the acceleration due to gravity is 9.8 m/s².

Discussion Character

  • Exploratory, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to find a common variable to relate the positions of both objects over time but expresses difficulty in starting the problem. Some participants ask for clarification on the original poster's approach, while others suggest using displacement equations to set the heights equal to each other.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem and attempting to clarify the original poster's reasoning. Some guidance has been offered regarding the use of displacement equations, but there is no explicit consensus on a solution yet.

Contextual Notes

The original poster indicates uncertainty in their approach and expresses a lack of direction in solving the problem. There may be constraints related to the homework requirements that are not fully articulated in the discussion.

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Homework Statement


An object is thrown downward with an initial speed of 4 m/s from a height of 99m above the ground. At the same instant, a second object is propelled vertically from the ground level with a speed of 25 m/s.
The acceleration of gravity is 9.8 m/s^2.
At what height above the ground will the two objects pass each other? Answer in units of m.


Homework Equations


http://www.glenbrook.k12.il.us/gbssci/phys/Class/1DKin/U1L6a1.gif

The Attempt at a Solution


Well I tried to find a common variable to plug in. I tried to plug in the position, then find time, then find the position, but it didnt work. Any help is appreciated.
 
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Can you show exactly what you did?
 
What I did didn't work. I kind just mushed stuff together. I might as well have said "I didnt know where to start" because I didnt.
 
dvdqnoc said:
What I did didn't work. I kind just mushed stuff together. I might as well have said "I didnt know where to start" because I didnt.

the equation to use is:

d = v1*t + (1/2)at^2

now use d = X - Xo

X - Xo = v1*t + (1/2)at^2

so: X = Xo + v1*t + (1/2)at^2

X is the height at any time t. Xo is the initial height.

use this to get the displacement equations for each of the 2 objects...

after you do that, set them equal... solve for t...
 
Last edited:

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