An object is thrown downward with an initial speed of 6 m/s from a height of 42 m above the ground. At the same instant, a second object is propelled vertically up from ground level with a speed of 55 m/s. At what height above the ground will the two objects pass each other? The acceleration of gravity is 9.8 m/s² 2. The attempt at a solution Let h = height above the ground where they pass each other. 42 - h = 6t + 4.95t² and h = -55t + 4.95t² Adding, 42 = -49t + 4.95t² I don't know where to go from here. Should I use Quadratic formula to find the t? I'm confused.