An object is thrown downward with an initial speed of 6 m/s from a height of 42 m above the ground. At the same instant, a second object is propelled vertically up from ground level with a speed of 55 m/s. At what height above the ground will the two objects pass each other?(adsbygoogle = window.adsbygoogle || []).push({});

The acceleration of gravity is 9.8 m/s²

2. The attempt at a solution

Let h = height above the ground where they pass each other.

42 - h = 6t + 4.95t²

and h = -55t + 4.95t²

Adding, 42 = -49t + 4.95t²

I don't know where to go from here. Should I use Quadratic formula to find the t? I'm confused.

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# Homework Help: FInd the height where two object pass each other.

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