The discussion focuses on calculating the magnetic force on a conductor with a current of 6A, positioned at an angle of 60° to a magnetic field of intensity 1.2 T. The formula used is F = IlB sin θ, resulting in a force of 0.436 N. To determine the direction of the magnetic force, the vector equation F = q(V x B) is referenced, emphasizing the importance of understanding the cross product in vector calculations.
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Arooj said:Homework Statement
Find the force on 7.0 cm of conductor bearing a current of 6A if it lies perpendicular to a magnetic field of intensity 1.2 T and the wire makes an angle of 60° with the magnetic field?
Homework Equations
F = IlB sin θThe Attempt at a Solution
The magnetic force is easy to find:
F = 6 * (7/100) * 1.2 * (sin 60)
F = 0.436
How do you find the direction of the force?