Potential and wave number problem (concerning units)

Click For Summary

Homework Help Overview

The discussion revolves around a potential energy equation for a molecule, specifically focusing on the constants involved and their units. The original poster presents a formula for potential energy and seeks clarification on the units of various constants, particularly in the context of atomic units.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Participants explore the physical meaning of constants A and c, questioning their units and how they relate to the potential energy equation. There is an attempt to derive the value of c and discuss the implications of using atomic units.

Discussion Status

The discussion is ongoing, with some participants providing insights into the nature of atomic units and their application. There is a recognition of the need for clarity regarding the constants and their physical representations, but no consensus has been reached on the interpretation of units.

Contextual Notes

Participants note that the problem lacks specific information about the constants A and c, leading to uncertainty about their physical significance and units. The original poster expresses confusion regarding the feather constant's units and how to derive them in the context of atomic units.

Lindsayyyy
Messages
215
Reaction score
0
Hi everyone I have the following problem:

Homework Statement



Give is the following potential for a molecule:

[tex]E_s(R)=E_s(\infty)-\frac {1}{R}+A*exp(-cR)[/tex]

whereas E_s(infinity)=1.49 eV. A and c are constants which I want to calculate. R(equilibrium) is given as 2.36 Angström and the wave number for the lowest state is v=364,6 cm^-1



Homework Equations





The Attempt at a Solution



So far so good I already got the solution for this, but I have troubles concerning the units. If you take a look at the potential you have 1/R [m^-1] and E_s(infninity) whichs unit is [eV].

When I try to calculate c I derive the potential and use that the second derivation is the feather constant. I come to:

[tex]c=k*{R_0}^2 +\frac {2}{R_0}[/tex]

whereas k is the feather constant and R0 the radius at the equilibrium.
The soluton for k should be: 0.0698 atomic units.

But I have no idea how to get there. I'm also conernced about the units because I only knew about N/m or kg/s^2 for k.

Can anyone help me with this?

Thanks in advance
 
Physics news on Phys.org
Not really enough information ... what are each of the constants supposed to represent physically?
i.e. if I take c=speed of light, then c=137 in Hartree atomic units.

http://en.wikipedia.org/wiki/Atomic_units
 
That information is not given. The task says that A and c are just constants whereas I shall find the values of each.

If I look at the potential c must have the unit m^-1 and A Joule
 
If I look at the potential c must have the unit m^-1 and A Joule
Not if you are using atomic units.
Energy is given in Hartree energies and distance as a multiple of the Bohr radius.

You can't just read the units off like that:
If you look at the original expression, that 1/R must have dimensions of energy right?
If R has dimensions of length, then the "1" in 1/R must have dimensions of energy x length ...

... that's why you need to know where things come from.
Though, as long as the algebra is right, then putting atomic units in will get you atomic units out.
From what I see, c and k should be dimensionless.
 
Ok thank you,

I got the solution (the values of c and A) but I try to understand it. My first problem is that the solution says that the feather constants units are atomic units. How do I get there? (Value is written in my first post).
 
I gave you a link to atomic units earlier - did you read it?
 

Similar threads

Replies
1
Views
3K
  • · Replies 13 ·
Replies
13
Views
3K
  • · Replies 23 ·
Replies
23
Views
2K
Replies
1
Views
1K
Replies
5
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
6
Views
2K