Potential/conservation of energy

[kappcity06]

no its 500 m long and 300 m high

 

[kappcity06]

using a^2+b^2=c^2 i found it to be 583.1

or should i use the 500

 

[kappcity06]

ok that right sry

 

[kappcity06]

ok part b is now correct for part c i need to find kentic enery.

 

[sdekivit]

using a^2+b^2=c^2 i found it to be 583.1

or should i use the 500

you mean that the horizontal length is 500 m ? then $$F_{N}$$ must be recalculated with angle = $$tan^{-1} \frac{3} {5}$$

the rest is the same.

I thought the length of the hill you meant the hypotenuse of the triangle

 

[kappcity06]

its ok 500 is correct length

 

[kappcity06]

i need to work on part c now

 

[sdekivit]

i need to work on part c now

you get part b now by drawing a triangle and use geometry and the 2 vectors you need to draw from the gravitational force ?

--> you now have $$E_{friction}$$ and you can go on with the energy balance i wrote down in one of my earliest replies.

 

[kappcity06]

i got part c and d
thanks to all who hlepd i am really greatful