Potential difference calculation

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In potential difference calculations, a wire is treated as 'perfect,' meaning the potential is uniform along its length. Consequently, when two resistors are connected by a wire, the ends of the resistors are at the same potential. This principle is crucial for solving school problems related to electrical circuits. Understanding this concept ensures accurate calculations of potential differences across components. Accurate application of these principles is essential for mastering circuit analysis.
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Homework Statement
for the 2 resistors in parallel, is is true that only need to find p.d across one of them (eg. (5.0)(1.0)=5.0V) to determine the p.d across both parallel resistors ? in this case (2.0.)(2.5) = (5.0)(1.0), but what If the p.d across resistor A not equal to that of B, then which resistor do you calculate the p.d of?
Relevant Equations
V=IR
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That cannot happen.
 
For these types of school problems, a wire is considered to be 'perfect'; specifically that is: "The potential at any point on a wire is the same as the potential at any other point on that wire."

Keeping that in mind, since the respective ends of the two resistors A and B are connected by wire, they are at exactly the same potential.

Hope this helps!

Cheers,
Tom
 
Thread 'Correct statement about size of wire to produce larger extension'
The answer is (B) but I don't really understand why. Based on formula of Young Modulus: $$x=\frac{FL}{AE}$$ The second wire made of the same material so it means they have same Young Modulus. Larger extension means larger value of ##x## so to get larger value of ##x## we can increase ##F## and ##L## and decrease ##A## I am not sure whether there is change in ##F## for first and second wire so I will just assume ##F## does not change. It leaves (B) and (C) as possible options so why is (C)...

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