Potential difference question - Immediate

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Homework Help Overview

The discussion revolves around understanding the relationship between terminal voltage, emf, and current in a battery circuit. The original poster is trying to analyze a circuit involving a battery with given emf and internal resistance, specifically when the terminal voltage is -40V.

Discussion Character

  • Conceptual clarification, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to apply Kirchhoff's loop rule but expresses confusion about the role of terminal voltage versus applied voltage. They question the direction of current flow and the definitions of voltage between points A and B.

Discussion Status

Participants are exploring different interpretations of voltage definitions and current direction. Some have offered clarifications regarding voltage conventions and the implications of terminal voltage in the context of the circuit. There is an ongoing examination of assumptions related to the voltage readings and their meanings.

Contextual Notes

Participants are working with limited information, primarily the values provided in the original post, and are discussing the implications of these values on the circuit analysis. The discussion reflects uncertainty about voltage conventions and the setup of the problem.

MathewsMD
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The emf and internal resistance are shows in the attached image. When the terminal voltage, Vba, is equal to -40V, what is the current through the battery, including its direction?

Solution:

VT = emf - iR (general)

In this case, VT = 40V, when considering VT = Vab = Vb - Va

VT = Vext - 28V - i(1.5Ω)

Now, I'm not entirely certain of where I went wrong, but don't seem to know much about the current besides that it is going from a to b in the cell.

The solution shows the answer is 8.0A but I can only get that if I do 0 = 40V - 28V - i(1.5Ω) but I don't quite see how you can apply the 40V inside (using Kirchoff's loop rule) if that's the terminal voltage instead of the applied voltage from an external source. Any clarification on what I am doing wrong or what I should do, and clarification on VT would be helpful.

This is what I quickly used as a reference: http://www.physics.ucla.edu/demoweb...d_magnetism/dc_circuits/terminal_voltage.html
 

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Vba : is A positive compared to B, or vice-versa?
 
rude man said:
Vba : is A positive compared to B, or vice-versa?

All I'm given is what I have given you. Since Vba = -40V, Vab = 40V and I was under the impression then that b is the + side and a is -. Am I mistaken?

Also, when they say current goes from a to b, do they mean in the cell itself or outside? If it is outside, then this makes sense and I think they are trying to say then that it is a that is + and b that is -. But any explanation for how one would come to that conclusion simply given everything I have given you would be great! Thanks!
 
Vab = Vb - Va

Not correct.
VT = Vext - 28V - i(1.5Ω)

This doesn't look right.

EDIT
You'll find it easier if you picture b as 0v, and making every other point positive wrt end b.

The voltage between b and a is the terminal voltage.
 
Last edited:
NascentOxygen said:
Not correct.




This doesn't look right.

EDIT
You'll find it easier if you picture b as 0v, and making every other point positive wrt end b.

The voltage between b and a is the terminal voltage.

Oh, so Vba = Va - Vb? If so, that's where I went wrong. I just don't know why I've haven't up on this convention...
 
MathewsMD said:
Oh, so Vba = Va - Vb?
No.

Vba is read as "the voltage of b wrt a".
 
Imagine charging a 28 V battery using a 40 V source.
If Vba = - 40 V, Vab is 40 V. 28 of those are over the battery, the remainder over the 1.5 Ω. There is only 1 current and it's going all round.
 

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