Potential difference required to stop a particle

Click For Summary
SUMMARY

The discussion centers on calculating the electric potential difference required to stop a charged particle with a charge-to-mass ratio of 50 C/kg moving at a speed of 200 m/s. The relevant equation used is the kinetic energy formula, \(\frac{1}{2}mv^2 = qV\), where \(q\) is the charge and \(V\) is the potential difference. By substituting the charge-to-mass ratio into the equation, the mass cancels out, allowing for the determination of the required potential difference directly from the given parameters.

PREREQUISITES
  • Understanding of kinetic energy calculations
  • Familiarity with electric potential and voltage concepts
  • Knowledge of charge-to-mass ratio implications
  • Basic principles of electric forces and fields
NEXT STEPS
  • Study the relationship between kinetic energy and electric potential energy
  • Learn about charge-to-mass ratio applications in particle physics
  • Explore the concept of electric fields and forces on charged particles
  • Investigate the derivation of the kinetic energy formula in classical mechanics
USEFUL FOR

Students in physics, particularly those studying electromagnetism and mechanics, as well as educators looking for practical examples of electric potential calculations.

Revvi
Messages
7
Reaction score
0

Homework Statement



A particle with a charge-to-mass ratio of 50 C/kg is moving at a speed of 200 m/s. What electric potential difference is required to stop the particle?

Homework Equations



F = Eq?

The Attempt at a Solution



I am completely uncertain how to start this problem. Perhaps somebody can start me off?
 
Physics news on Phys.org
Remember that voltage is work per unit charge. Do you remember how to calculate the energy of a moving particle from your mechanics?

\frac{1}{2}mv^2=qV
To find q, you need to multiply mass into that charge per mass value. The unknown mass cancels on both sides.
 

Similar threads

Replies
11
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 14 ·
Replies
14
Views
2K
Replies
1
Views
2K
  • · Replies 4 ·
Replies
4
Views
4K
Replies
8
Views
2K
Replies
6
Views
2K
  • · Replies 30 ·
2
Replies
30
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
4
Views
6K