Calculating Potential Energy from Force for Non-Linear Systems

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SUMMARY

The discussion focuses on calculating potential energy from a force defined by the equation F(x) = αx - βx³ for non-linear systems. The relationship between force and potential energy is established through the equation -dV(x)/dx = F(x). Participants confirm that the choice of zero-level for potential energy is arbitrary and does not influence the physical outcomes, allowing for the simplification that V(0) can be set to zero without loss of generality.

PREREQUISITES
  • Understanding of classical mechanics principles, particularly force and potential energy relationships.
  • Familiarity with calculus, specifically integration techniques.
  • Knowledge of non-linear dynamics and their mathematical representations.
  • Basic grasp of physical constants and their implications in potential energy calculations.
NEXT STEPS
  • Explore integration techniques for non-linear functions in physics.
  • Study the implications of potential energy in non-linear systems.
  • Learn about the role of integration constants in physical equations.
  • Investigate other forms of force equations and their corresponding potential energy calculations.
USEFUL FOR

Students and professionals in physics, particularly those focusing on mechanics and non-linear systems, as well as researchers interested in potential energy calculations and their applications in various physical contexts.

RubroCP
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Homework Statement
##F(x)=\alpha x-\beta x^3##
Relevant Equations
##-\frac{\mathrm{d}V(x)}{\mathrm{d}x}=F(x)##
If I have a force that behaves according to the formula ##F(x)=\alpha x-\beta x^3##, how can I get the potential energy from it? I know that:
$$-\frac{\mathrm{d}V(x)}{\mathrm{d}x}=F(x),$$
but what about the limits of the integration?
 
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The integration constant is not physical as it does not affect the force. It is up to you to choose the zero-level of the potential.
 
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Orodruin said:
The integration constant is not physical as it does not affect the force. It is up to you to choose the zero-level of the potential.
So can I say without loss of generality that for x = 0 the potential is also null?
 
Yes, this will not affect the physics.
 
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Orodruin said:
Yes, this will not affect the physics.
Thanks!
 

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