Potential Gradient of potentiometer wire

[Tanishq Nandan]

Homework Statement

The resistivity of a potentiometer wire is (40×10^-8) ohm-m and the area of cross section is (8×10^-6)m^2.If 0.2 amp current is flowing through the wire,then the potential gradient will be??

Homework Equations

1.Resistance=[(Resisitvity)×(Length)]/(Cross-sectional area)
2.V=IR
3.Potential gradient of wire= (Potential difference across wire)/(Length of wire)

The Attempt at a Solution

▪Assuming the length of the wire to be l, and using formula 1,we can find the resistance of the wire.
▪Using formula 2,potential difference across the wire can be found,since we know the current flowing through the wire(which will obviously come in terms of l).
▪Using formula 3,we can get the value of potential gradient.
Problem:My answer is coming 1Vm^-1 whereas the answer given is 0.01Vm^-1
IF THE ANSWER GIVEN SEEMS TO BE WRONG,KINDLY REPLY SO.

 

[willem2]

You use the right method, but your answer is wrong. Are you sure you have all units in meters?

 

[Tanishq Nandan]

You use the right method, but your answer is wrong. Are you sure you have all units in meters?

Yeah,they are in meters,but don't worry about it.I got it just now,had been commiting a silly mistake(blunder,crime,punishable by death).Simple calculation error. (I wrote 10^-8 divided by 10^-6 as 1,whereas it should have been 0.01).
But,thanks anyway!