Power Calc: Find Current & Power in Circuit - Resistors Absorbing?

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SUMMARY

The discussion centers on analyzing a circuit involving a resistor and a voltage source, specifically determining the current flowing through the resistor and the power absorbed or supplied by each component. The current, denoted as iR, is established at 2A, leading to a voltage across the resistor of 10V using Ohm's Law. It is clarified that while resistors dissipate power as heat, they can also deliver power to other elements in the circuit, with the voltage source absorbing power. The power values calculated for the current source, resistor, and voltage source are -20W, 0W, and 20W, respectively.

PREREQUISITES
  • Understanding of Ohm's Law (U = IR)
  • Familiarity with Kirchhoff's Current Law (KCL)
  • Knowledge of Kirchhoff's Voltage Law (KVL)
  • Concept of power in electrical circuits (P = IV)
NEXT STEPS
  • Study the concept of power dissipation in resistors using the formula P = I²R
  • Learn about independent current and voltage sources in circuit analysis
  • Explore the implications of power absorption and supply in circuit components
  • Investigate the role of polarity in determining power flow in circuits
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in analyzing or designing electrical circuits will benefit from this discussion.

kexanie
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Homework Statement


Concider the circuit shown below. Find the current iR flowing through the resitor. Find the power for each element in the circuit. Which elements are absorbing power?

Homework Equations


Ohm's law: U = IR;
Kirchhoff's Current Law and Kirchhof's Voltage Law.

The Attempt at a Solution


My instructor told me that the resistor is supplying power and the voltage source is absorbing power. But I just didn't get it.
By the diagram, the current iR flows in a clockwise direction. With KCL, iR = 2A, and with Ohm's law, vR = iRR = 10V. But How can I know whether the resistor is absorbing power or supplying power? Because I can't determine the polarity between the resitor with KVL.
It's clear that the voltage source is absorbing power, and if it were a battery, it would be charging.
But I can't understand how can a resistor SUPPLY power to other elements in the circuit as my instructor told me.
 

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Is that 2A a current source or ammeter?
 
PhysicoRaj said:
Is that 2A a current source or ammeter?
It's an independent current source, and 10V is an independent voltage source.
 
kexanie said:

Homework Statement


Concider the circuit shown below. Find the current iR flowing through the resitor. Find the power for each element in the circuit. Which elements are absorbing power?

Homework Equations


Ohm's law: U = IR;
Kirchhoff's Current Law and Kirchhof's Voltage Law.

The Attempt at a Solution


My instructor told me that the resistor is supplying power and the voltage is absorbing power. But I just didn't get it.
By the diagram, the current iR flows in a clockwise direction. With KCL, iR = 2A, and with Ohm's law, vR = iRR = 10V. But How can I know whether the resistor is absorbing power or supplying power? Because I can't determine the polarity between the resitor with KVL.
It's clear that the voltage source is absorbing power, and if it were a battery, it would be charging.
But I can't understand how can a resistor SUPPLY power to other elements in the circuit as my instructor told me.
Hi kexanie.

http://img96.imageshack.us/img96/5725/red5e5etimes5e5e45e5e25.gif

I believe what your instructor intended you to understand is that through the resistor is power delivered to the voltage source. It is the constant current source that supplies this power. Resistors always dissipate heat, according to the I2•R formula, but there is nothing to say that the current can't then go on to deliver power to another element.
 
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NascentOxygen said:
Hi kexanie.

http://img96.imageshack.us/img96/5725/red5e5etimes5e5e45e5e25.gif

I believe what your instructor intended you to understand is that through the resistor is power delivered to the voltage source. It is the constant current source that supplies this power. Resistors always dissipate heat, according to the I2•R formula, but there is nothing to say that the current can't then go on to deliver power to another element.

so can we tell that the power of the current source, the resitor and the voltage source are respectively -20W, 0W and 20W since the resitor just give out what it absorb from the current source?
 
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kexanie said:

Homework Statement


Concider the circuit shown below. Find the current iR flowing through the resitor. Find the power for each element in the circuit. Which elements are absorbing power?

Homework Equations


Ohm's law: U = IR;
Kirchhoff's Current Law and Kirchhof's Voltage Law.

The Attempt at a Solution


My instructor told me that the resistor is supplying power and the voltage source is absorbing power. But I just didn't get it.
By the diagram, the current iR flows in a clockwise direction. With KCL, iR = 2A, and with Ohm's law, vR = iRR = 10V. But How can I know whether the resistor is absorbing power or supplying power? Because I can't determine the polarity between the resitor with KVL.
It's clear that the voltage source is absorbing power, and if it were a battery, it would be charging.
But I can't understand how can a resistor SUPPLY power to other elements in the circuit as my instructor told me.

attachment.php?attachmentid=67436&d=1394358223.png
What is the voltage drop across the resistor? (in the direction of current flow)

What is the voltage drop across the voltage source? (in the direction of current flow)
 
kexanie said:
so can we tell that the power of the current source, the resitor and the voltage source are respectively -20W, 0W and 20W since the resitor just give out what it absorb from the current source?
All electrical power a resistor 'absorbs' is turned into heat.
 
SammyS said:
What is the voltage drop across the resistor? (in the direction of current flow)

What is the voltage drop across the voltage source? (in the direction of current flow)

1)By Ohm's law, the voltage drop across the resitor is 10 V? How can I know the polarity of that voltage?

2)Is it just 10 V? I am not sure. But by the definition of an independent voltage source, it should be 10 V.
 
kexanie said:
1)By Ohm's law, the voltage drop across the resistor is 10 V? How can I know the polarity of that voltage?

2)Is it just 10 V? I am not sure. But by the definition of an independent voltage source, it should be 10 V.
Going around the circuit clockwise, the same direction in which the current is forced to flow, yes the voltage drops by 10 Volts as it flows through the resistor. (Now you can find the power )

Continuing in the same direction, how much does the voltage change as current passes through the voltage source?
 
  • #10
SammyS said:
Going around the circuit clockwise, the same direction in which the current is forced to flow, yes the voltage drops by 10 Volts as it flows through the resistor. (Now you can find the power )

Continuing in the same direction, how much does the voltage change as current passes through the voltage source?

Sorry for grammar mistakes.

1) I can easily tell that the magnitude of that power is 10 W, but should it be negative or positive? I can't tell the polarity of the voltage dropped across the resistor. That's why I am asking.

2) I don't know. Do you mean electric potential by voltage?
 
  • #11
kexanie said:
1) I can easily tell that the magnitude of that power is 10 W, but should it be negative or positive? I can't tell the polarity of the voltage dropped across the resistor. That's why I am asking
Current flows through the resistor from the higher potential end to the lower potential end, e.g., from positive towards negative, and this is described as a voltage drop.
 

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