Power Calc: Find Current & Power in Circuit - Resistors Absorbing?

AI Thread Summary
The discussion revolves around understanding power flow in a circuit involving a resistor and a voltage source. The current through the resistor is calculated to be 2A, with a voltage drop of 10V across it, indicating that the resistor dissipates power as heat. The confusion arises regarding whether the resistor is supplying or absorbing power; it is clarified that the resistor always dissipates power, while the current source provides power to the circuit. The voltage source is identified as absorbing power, similar to a battery charging. Ultimately, the resistor's power is determined to be 10W, with the current source supplying power and the voltage source absorbing it.
kexanie
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Homework Statement


Concider the circuit shown below. Find the current iR flowing through the resitor. Find the power for each element in the circuit. Which elements are absorbing power?

Homework Equations


Ohm's law: U = IR;
Kirchhoff's Current Law and Kirchhof's Voltage Law.

The Attempt at a Solution


My instructor told me that the resistor is supplying power and the voltage source is absorbing power. But I just didn't get it.
By the diagram, the current iR flows in a clockwise direction. With KCL, iR = 2A, and with Ohm's law, vR = iRR = 10V. But How can I know whether the resistor is absorbing power or supplying power? Because I can't determine the polarity between the resitor with KVL.
It's clear that the voltage source is absorbing power, and if it were a battery, it would be charging.
But I can't understand how can a resistor SUPPLY power to other elements in the circuit as my instructor told me.
 

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Is that 2A a current source or ammeter?
 
PhysicoRaj said:
Is that 2A a current source or ammeter?
It's an independent current source, and 10V is an independent voltage source.
 
kexanie said:

Homework Statement


Concider the circuit shown below. Find the current iR flowing through the resitor. Find the power for each element in the circuit. Which elements are absorbing power?

Homework Equations


Ohm's law: U = IR;
Kirchhoff's Current Law and Kirchhof's Voltage Law.

The Attempt at a Solution


My instructor told me that the resistor is supplying power and the voltage is absorbing power. But I just didn't get it.
By the diagram, the current iR flows in a clockwise direction. With KCL, iR = 2A, and with Ohm's law, vR = iRR = 10V. But How can I know whether the resistor is absorbing power or supplying power? Because I can't determine the polarity between the resitor with KVL.
It's clear that the voltage source is absorbing power, and if it were a battery, it would be charging.
But I can't understand how can a resistor SUPPLY power to other elements in the circuit as my instructor told me.
Hi kexanie.

http://img96.imageshack.us/img96/5725/red5e5etimes5e5e45e5e25.gif

I believe what your instructor intended you to understand is that through the resistor is power delivered to the voltage source. It is the constant current source that supplies this power. Resistors always dissipate heat, according to the I2•R formula, but there is nothing to say that the current can't then go on to deliver power to another element.
 
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NascentOxygen said:
Hi kexanie.

http://img96.imageshack.us/img96/5725/red5e5etimes5e5e45e5e25.gif

I believe what your instructor intended you to understand is that through the resistor is power delivered to the voltage source. It is the constant current source that supplies this power. Resistors always dissipate heat, according to the I2•R formula, but there is nothing to say that the current can't then go on to deliver power to another element.

so can we tell that the power of the current source, the resitor and the voltage source are respectively -20W, 0W and 20W since the resitor just give out what it absorb from the current source?
 
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kexanie said:

Homework Statement


Concider the circuit shown below. Find the current iR flowing through the resitor. Find the power for each element in the circuit. Which elements are absorbing power?

Homework Equations


Ohm's law: U = IR;
Kirchhoff's Current Law and Kirchhof's Voltage Law.

The Attempt at a Solution


My instructor told me that the resistor is supplying power and the voltage source is absorbing power. But I just didn't get it.
By the diagram, the current iR flows in a clockwise direction. With KCL, iR = 2A, and with Ohm's law, vR = iRR = 10V. But How can I know whether the resistor is absorbing power or supplying power? Because I can't determine the polarity between the resitor with KVL.
It's clear that the voltage source is absorbing power, and if it were a battery, it would be charging.
But I can't understand how can a resistor SUPPLY power to other elements in the circuit as my instructor told me.

attachment.php?attachmentid=67436&d=1394358223.png
What is the voltage drop across the resistor? (in the direction of current flow)

What is the voltage drop across the voltage source? (in the direction of current flow)
 
kexanie said:
so can we tell that the power of the current source, the resitor and the voltage source are respectively -20W, 0W and 20W since the resitor just give out what it absorb from the current source?
All electrical power a resistor 'absorbs' is turned into heat.
 
SammyS said:
What is the voltage drop across the resistor? (in the direction of current flow)

What is the voltage drop across the voltage source? (in the direction of current flow)

1)By Ohm's law, the voltage drop across the resitor is 10 V? How can I know the polarity of that voltage?

2)Is it just 10 V? I am not sure. But by the definition of an independent voltage source, it should be 10 V.
 
kexanie said:
1)By Ohm's law, the voltage drop across the resistor is 10 V? How can I know the polarity of that voltage?

2)Is it just 10 V? I am not sure. But by the definition of an independent voltage source, it should be 10 V.
Going around the circuit clockwise, the same direction in which the current is forced to flow, yes the voltage drops by 10 Volts as it flows through the resistor. (Now you can find the power )

Continuing in the same direction, how much does the voltage change as current passes through the voltage source?
 
  • #10
SammyS said:
Going around the circuit clockwise, the same direction in which the current is forced to flow, yes the voltage drops by 10 Volts as it flows through the resistor. (Now you can find the power )

Continuing in the same direction, how much does the voltage change as current passes through the voltage source?

Sorry for grammar mistakes.

1) I can easily tell that the magnitude of that power is 10 W, but should it be negative or positive? I can't tell the polarity of the voltage dropped across the resistor. That's why I am asking.

2) I don't know. Do you mean electric potential by voltage?
 
  • #11
kexanie said:
1) I can easily tell that the magnitude of that power is 10 W, but should it be negative or positive? I can't tell the polarity of the voltage dropped across the resistor. That's why I am asking
Current flows through the resistor from the higher potential end to the lower potential end, e.g., from positive towards negative, and this is described as a voltage drop.
 
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