Power Law Equation Help: Solving for v with x=0.02 | Homework Equations

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Homework Help Overview

The discussion revolves around solving for the variable v in the context of a power law equation, given a specific value for x (0.02). The equation provided is v(x) = 47.8 ⋅ (0.451/x)^(5.39).

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss whether taking the logarithm of both sides is an appropriate method for solving for v. Some express confusion about the necessity of substituting the known value of x into the equation.

Discussion Status

The discussion is ongoing, with some participants suggesting that substituting x=0.02 directly into the equation is sufficient to evaluate v. Others are exploring the implications of solving for v versus evaluating it at a specific point.

Contextual Notes

There is some confusion regarding the interpretation of the problem statement and the approach to solving it, particularly in relation to the application of calculus concepts and the clarity of the problem's requirements.

Adam_9333
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Homework Statement


need to solve for v? I also know the value of x=0.02

Homework Equations


v(x)= 47.8 ⋅ (0.451/x)^(5.39)

The Attempt at a Solution


how do I take the log of both sides, is that the right approach to solve for v?
 
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Apply the product rule then the power rule.
 
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But, if you already know x, you don't have anything to solve. Just put .02 in for x and evaluate.
 
I am little confused, my calculus skills stayed in first year. Do put 0.02 in the x term on the left side of the equation also, and just solve for V?
 
Adam_9333 said:
I am little confused, my calculus skills stayed in first year. Do put 0.02 in the x term on the left side of the equation also, and just solve for V?
You didn't state the problem accurately, but if it's asking you to determine v(0.02), then all you have to do is to replace the x on the right by 0.02 and perform the computations. To "solve for v" would be to find an equivalent equation with v alone on one side, but the equation is already of that form, so what you need to do to solve for v is nothing at all.

Adam_9333 said:
how do I take the log of both sides, is that the right approach to solve for v?
That would be a good approach if you wanted to solve for x.
 

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