Power of EM Wave Absorbed by Circular Disk of Radius 2m

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SUMMARY

The discussion centers on calculating the power transmitted to a circular disk with a radius of 2 meters when exposed to a plane polarized electromagnetic wave with an Erms of 30 V/m. The correct formula for intensity is I = Erms^2 / (cμ0), where μ0 is the permeability of free space (4 × 10–7 N•s^2/C^2). The user initially calculated the power using the area of the disk (A = πr^2) but mistakenly included an additional π factor, leading to an incorrect answer of 94.2 instead of the correct value of 30.

PREREQUISITES
  • Understanding of electromagnetic wave properties
  • Familiarity with the intensity formula I = P/A
  • Knowledge of the constants c (speed of light) and μ0 (permeability of free space)
  • Basic skills in algebra for manipulating equations
NEXT STEPS
  • Review the derivation of the intensity formula I = Erms^2 / (cμ0)
  • Study the relationship between power, intensity, and area in electromagnetic contexts
  • Explore the implications of polarization on electromagnetic wave absorption
  • Investigate common mistakes in applying formulas in physics problems
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone involved in solving problems related to electromagnetic wave interactions with materials.

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Homework Statement


A plane polarized electromagnetic wave propagates
with Erms = 30 V/m. What is the power transmitted to
a circular disk of radius r = 2m, if all of the light is
absorbed by the disk and S is perpendicular to the
disk?


Homework Equations


There is a passage that goes along with this that states that I =Erms^2/(cμ0), and that I = P/A. u0 = 4 × 10–7 N•s^2/C^2.



The Attempt at a Solution


Basically, I plugged in the values of Erms and μ0 into the Intensity equation and then multiplied by A (pi*4) to get 94.2.

But the answer key says the answer is 30 and that instead of multiplying by pi*r^2, you multiply by r^2. Please help!
 
Physics news on Phys.org
Where is the other pi?
 
You'll just have to try to understand the problem to see.
 

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