Power particle-like object problem

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The discussion focuses on calculating the instantaneous power of a particle-like object subjected to a force vector F = (5.0 N) i - (1.0 N) j + (10.0 N) k and a velocity vector v = - (2.0 m/s) i + (4.0 m/s) k. The correct method involves taking the dot product of the force and velocity vectors to determine the power, which is defined as P = F · v. Additionally, when the velocity has only a j component and the instantaneous power is -12 W, the velocity can be found by equating the dot product of the force and the velocity to the given power.

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Hi, I've been trying to complete this question for almost an hour, i was hoping you could provide some advice

At a certain instant, a particle-like object is acted on by a force F = (5.0 N) i hat - (1.0 N) j hat + (10.0 N) k hat while the object's velocity is v = - (2.0 m/s) i hat + (4.0 m/s) k hat. 1)What is the instantaneous rate at which the force does work on the object?

2)At some other time, the velocity consists of only a j component. If the force is unchanged, and the instantaneous power is -12 W, what is the velocity of the object just then?

I tried taking the dot product of the force and velocity, making sure i only multiplied the like terms of the unit vectors. then i took the hypotenuse using pythagoras, but the answer i get is 41.2 Watts and its not right? please could someone help?
 
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critch said:
I tried taking the dot product of the force and velocity, making sure i only multiplied the like terms of the unit vectors. then i took the hypotenuse using pythagoras, but the answer i get is 41.2 Watts and its not right? please could someone help?

1) Taking the dot product is enough. I didn't quite understand what you have done after that.

2) Suppose the velo is v = vj. Find F.v and equate it to the instantaneous power given.
 

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