Why does 5|x-2|<7 instead of 5|x-2|<1 for this power series?

Join the discussion
Registration is free. Start your own thread to ask a follow-up.
1 reply · 1K views
cue928
Messages
129
Reaction score
0
For the following power series: n=1 to infinity [(5^n)(x-2)^n]/8n^7
I used the ratio test, which I understand, but why does the book say it is convergent for
5|x-2|<7? I had 5|x-2|<1, but I don't understand why it would say 7?
 
Physics news on Phys.org
It would be 5|x-2|<7 if it were 7^n in the denominator instead of x^7. Probably a typo in either the question or the answer.