The discussion revolves around determining the domain of the function 14/(x² - x - 6) in interval notation. Participants are exploring how to express this domain correctly while addressing the implications of the function's denominator.
The discussion is ongoing, with participants providing feedback on each other's attempts. Some have pointed out issues with notation and the need for a union of intervals rather than a single interval. There is no explicit consensus yet on the correct domain representation.
Participants have noted the importance of correctly identifying values that lead to undefined expressions, such as division by zero, and the implications of using incorrect interval notation.
datafiend said:Homework Statement
What's the domain of 14/x2-x-6, in interval notation?
Homework Equations
\underline{14}x2-x-6
The Attempt at a Solution
[3, + infinity)
[-2,- infinity)
Sorry, I can't find the infinity symbol
Thx
datafiend said:Homework Statement
What's the domain of 14/(x2-x-6), in interval notation?Homework Equations
##\frac{14}{x^2-x-6}##
The Attempt at a Solution
[3, + infinity)
[-2,- infinity)
Sorry, I can't find the infinity symbol
Thx
The Attempt at a Solution
You mean 14/(x2- x- 6)= 14/((x- 3)(x+ 2))datafiend said:Homework Statement
What's the domain of 14/x2-x-6, in interval notation?
No, this is wrong because it does not include such numbers as x= 0 for which 14/(0- 0- 6)= -7/3 or x= -5 for which 14/(25+ 5- 6)= 7/12.Homework Equations
\underline{14}x2-x-6
The Attempt at a Solution
[3, + infinity)
Strictly speaking this is bad notation- it should be (-infinity, -2]. (The smaller goes on the left.)[-2,- infinity)
Sorry, I can't find the infinity symbol
Thx
Homework Statement
Homework Equations
The Attempt at a Solution
I'm surprised no one's mentioned the incorrect use of the square bracket to end the set.HallsofIvy said:Strictly speaking this is bad notation- it should be (-infinity, -2]. (The smaller goes on the left.)
But even that is not correct because it does not contain x= 0 and x= 5