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A Predicting Fermi Surface from Chemical Formula

  1. Sep 15, 2016 #1
    Hi, I was hoping I could get some things cleared up. Recently my Solid State professor mentioned that we could simply, from the chemical formula, predict where the band crossings are going to be. For example, take LaFeAsO. Since La has a valency of +3, Fe of +3, As of -3, and O of -2, he deducted from the lattice (which is more or less cubic), that the band crossings are going to be primarily from the Fe. However, I'm completely lost as to why. Any help is appreciated!
     
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  3. Sep 16, 2016 #2

    DrDu

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    This is a mainly ionic compound. Did you pay attention in your chemistry class? Then you should be able to name the valence orbitals of these elements and their occupation in the ions. For which element in your list aren't they neither full nor empty?​
     
  4. Sep 16, 2016 #3
    So, La is 5d1, Fe is 3d6, As is 4p3, and O is 2p4. So Fe is close to half filling. But, so is As and O. So can we just say the bandstructure will compose of mostly Fe because of the half filling? Therefore, it is highly metallic and also the binding energy of the 3d6 should be much smaller?
     
  5. Sep 16, 2016 #4

    DrDu

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    You didn't count well. Take in mind that these are ions.
     
  6. Sep 16, 2016 #5
    So Fe is 3d8. La is 5d3. On the right track?
     
  7. Sep 16, 2016 #6

    DrDu

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    No. Neutral La has 5d1 6s2, so La 3+ has none. Neutral Fe has 3d6 4s2, so what do you get for Fe 3+?
     
  8. Sep 16, 2016 #7
    I'm afraid I'm quite rusty in my chemistry here. So, Fe 3+ would be 3d5. However, I'm not sure where the 3+ for La is coming from (unless it's just because its a common oxidation state). How can one assume that the most common oxidation state is the right one to choose?
     
  9. Sep 17, 2016 #8

    DrDu

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    Solid state physics is in some respect inorganic chemistry specialized to molecules of infinite size. So you better polish your inorganic chemistry.
    Lanthanum has almost exclusively oxidation state 3+ just like oxygen mostly 2-. Iron mostly 2+ or 3+ and arsenic 3-, 3+ or 5+.
    The only reasonable combination to make this compound neutral is thus O 2-, As 3-, La 3+ and Fe 3+. Hence the valence shells on O and As are completely filled while the one of La is completely empty. If you form bands from these atomic states, they will be filled or empty, too. This leaves as the main suscpect only Fe whose d-orbitals are only partially filled and partially degenerate in a cubic environment (cf Ligand field theory).
     
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