Pressure at same height in same fluid?

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SUMMARY

The discussion centers on the pressure difference between two air pockets in a sealed tank filled with water. The pressure at point A is measured at 95 kPa absolute, while the pressure at point B is affected by the height difference of the water columns. The key conclusion is that the pressure at the bottom of the tank must be equal on both sides due to static equilibrium, despite the differing heights of water, which is influenced by the air pressure above the water. The pressure differential is calculated using the formula involving the densities of the fluids and gravitational acceleration.

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  • Understanding of fluid statics and hydrostatic pressure
  • Familiarity with the concepts of pressure differentials in fluids
  • Knowledge of the relationship between pressure, height, and density in fluids
  • Basic grasp of static equilibrium in fluid systems
NEXT STEPS
  • Study the principles of hydrostatic pressure and its applications in fluid mechanics
  • Learn about the effects of atmospheric pressure on fluid systems
  • Explore the concept of static equilibrium in greater detail
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This discussion is beneficial for students studying fluid mechanics, engineers working with hydraulic systems, and anyone interested in understanding the principles of pressure in static fluids.

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Homework Statement


A sealed has a partition stuck down in water, creating two separate air pockets. The pressure at A is measured to 95 kPa (absolute) and the temperature is 20 C. Find the pressure at B.

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The Attempt at a Solution


Why is the pressure at A not equal to B? Doing U-tube exercises one uses that the pressure at the same height in the same fluid is equal, which is not the case here. Is it because the tank is sealed?
 

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If I'm not mistaken:
Yes, it's because the tank is sealed. The water is at different heights so the pressure differential is given by:
$$\rho_A g h_1 - \rho_w g h_2 - \rho_B g h_3 \\ = g(2\rho_A - 2\rho_w) \\ = 2g(\rho_A-\rho_w)$$
assuming ##\rho_A = \rho_B##

its been a while since I've done fluids so i may indeed be mistaken, take it with a grain of salt :)
 
Yes.

When we think about the pressure under water we sometimes ignore the effect of the air above because it's roughly the same everywhere but that's not always valid. Changes in the air pressure above the water changes the pressure below the water. This can cause the sea to rise and fall in different places (an example is a storm surge).

Consider the pressure at the bottom of the tank. It must be the same pressure on the left as the right or fluid would flow horizontally. However the depth of water on the right is greater than that on the left by 2m. So something must be equalising the pressure at the bottom OK?

Imagine if the tank was open at the top. The water on the right would fall until it was equal both sides. So something else must be preventing this and equalising the pressure at the bottom. One way to think of it is that the water has already fallen a bit on the right and risen on the left. This increased air pressure on the left and reduced pressure on the right is what causes the pressure at the bottom to be equal.
 
Thanks! is it possible to prove that the pressure at the bottom of the tank HAVE to equal each other?
 
The fluid is static. ie. in equilibrium. Remember that you can think of pressure at a point as being exerted equally onto that point from all directions. So if the pressures were different at the bottom on the left and right, then there would be a net flow from high pressure to low pressure ie not static
 
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The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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