 #1
SpectraPhy09
 25
 3
 Homework Statement:

What is the average pressure on the triangular wall by the liquid ?
given :
density of liquid p
gravitational acc is g
For Dimensions of container please check the figure(i have attached please Check)
.( Assume Patm = 0)
 Relevant Equations:
 Pressure at a point, x distance below the free surface of the liquid = pgx
I have just started this topic so i Don't have much clearity about it .
In our school it was tought that
Pavg = (Pi + Pf)/2 ...(i)
If we have a cuboidal shape container then it should be pgh/2 ryt ?
But also Pavg = Ftotal on the wall /A ...(ii)
= (pgh²l/2)/lh = pgh/2
It it was a triangular wall then Pavg comes different
Using (i) Pavg = pgh/2
(ii) Pavg = pgh/3
Which is correct ? 😓
Using
In our school it was tought that
Pavg = (Pi + Pf)/2 ...(i)
If we have a cuboidal shape container then it should be pgh/2 ryt ?
But also Pavg = Ftotal on the wall /A ...(ii)
= (pgh²l/2)/lh = pgh/2
It it was a triangular wall then Pavg comes different
Using (i) Pavg = pgh/2
(ii) Pavg = pgh/3
Which is correct ? 😓
Using