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- Homework Statement
- What is the average pressure on the triangular wall by the liquid ?

given :

density of liquid p

gravitational acc is g

For Dimensions of container please check the figure(i have attached please Check)

.( Assume Patm = 0)

- Relevant Equations
- Pressure at a point, x distance below the free surface of the liquid = pgx

I have just started this topic so i Don't have much clearity about it .

In our school it was tought that

Pavg = (Pi + Pf)/2 ...(i)

If we have a cuboidal shape container then it should be pgh/2 ryt ?

But also Pavg = Ftotal on the wall /A ...(ii)

= (pgh²l/2)/lh = pgh/2

It it was a triangular wall then Pavg comes different

Using (i) Pavg = pgh/2

(ii) Pavg = pgh/3

Which is correct ?

Using

In our school it was tought that

Pavg = (Pi + Pf)/2 ...(i)

If we have a cuboidal shape container then it should be pgh/2 ryt ?

But also Pavg = Ftotal on the wall /A ...(ii)

= (pgh²l/2)/lh = pgh/2

It it was a triangular wall then Pavg comes different

Using (i) Pavg = pgh/2

(ii) Pavg = pgh/3

Which is correct ?

Using