What is the kinetic energy of a block as water pours out of a container?

In summary: You should be able to get the velocity of the mass (call it v_m) in terms of the given values, and then plug that into your equation for KE. In summary, The problem involves a block connected to a massless rod and plunger in a cylindrical container of water. The block is initially at rest, and the water pours out of the container through a pipe at the bottom. The questions ask for the pressure applied by the block to the water (using A1, m, and g) and the kinetic energy of the block as the water pours out (using m, g, A1, A2, P0, h, and ρ). The solution involves using Bernoulli's equation and the equation for
  • #1
byahnoob
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Homework Statement



A block of mass m is connected to a massless rod and plunger of area A1 on a cylindric container of water. At

the bottom of the container there is a pipe that leads to an opening of area A2 where the water pours out at a

velocity v. The block starts at rest with the plunger a distance h from the bottom of the container.

A] What pressure does the block apply to the water? Only use A1 , m, and g in your answer.

B] What kinetic energy does the block have as water pours from the opening? Express your answer in terms of m, g, A1 , A2 , P0 , h, and ρ .

HINT* - solving for 1⁄2 v2 will get you very close to an expression for K.

[ATTACHED PICTURE OF PROBLEM]

Homework Equations



F = PA
Bernoulli's equation
KE = 1/2mv^2

The Attempt at a Solution


A] F = PA
mg = PA1

answer:
mg/A1 = P

B] Using Bernoulli's equation
P + pgh = P0 + 1/2pv^2
mg/A1 + pgh = P0 + 1/2pv^2

REARRANGE

(1/p)(mg/A1 + pgh + P0) = 1/2v^2

answer:
KE = 1/2mv^2 = (m/p)(mg/A1 + pgh + P0)
AM I CORRECT OR WRONG? I don't know how to get that A2 to the answer of part B
 

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  • #2
There are two velocities here, which you need separate variables for: the velocity of the water from the outlet (the given v), and the velocity of the mass (for which you need another symbol) . There is a relationship between them.
 

1. How does a piston work in a fluid system?

A piston works by moving up and down within a cylinder that is filled with a fluid. This movement creates pressure within the fluid, which can then be used to power various mechanisms.

2. What is the purpose of a piston in a fluid system?

The purpose of a piston in a fluid system is to convert the energy of the fluid into mechanical energy. This can be used to power machinery or control the flow of the fluid.

3. How is the force of a piston calculated in a fluid system?

The force of a piston in a fluid system is calculated by multiplying the pressure of the fluid by the area of the piston. This is known as Pascal's law and is represented by the equation F = P x A, where F is the force, P is the pressure, and A is the area.

4. What are the different types of pistons used in fluid systems?

There are several types of pistons used in fluid systems, including single-acting pistons, double-acting pistons, and differential pistons. Single-acting pistons only have pressure applied on one side, while double-acting pistons have pressure applied on both sides. Differential pistons have different diameters on each side, allowing for different forces to be generated.

5. How are pistons used in real-world applications?

Pistons are used in a wide range of real-world applications, from engines to hydraulic systems. They are commonly used in car engines to convert the energy of fuel combustion into mechanical energy, as well as in pumps and compressors to move fluids and gases. They are also used in hydraulic systems to lift heavy loads and control the flow of fluids in industrial machinery.

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