What is the kinetic energy of a block as water pours out of a container?

  • Thread starter Thread starter byahnoob
  • Start date Start date
  • Tags Tags
    Fluid Piston
Click For Summary
SUMMARY

The discussion focuses on calculating the kinetic energy of a block connected to a plunger in a cylindrical water container as water exits through an opening. The pressure exerted by the block on the water is derived using the formula F = PA, leading to P = mg/A1. The kinetic energy (KE) of the block as water pours out is expressed as KE = (m/p)(mg/A1 + pgh + P0), utilizing Bernoulli's equation. The relationship between the velocities of the water exiting and the mass of the block is also highlighted as a critical aspect of the solution.

PREREQUISITES
  • Understanding of Bernoulli's equation
  • Knowledge of pressure calculations (F = PA)
  • Familiarity with kinetic energy formula (KE = 1/2mv^2)
  • Basic principles of fluid dynamics
NEXT STEPS
  • Explore the derivation of Bernoulli's equation in fluid mechanics
  • Learn about the relationship between fluid velocity and pressure in different cross-sectional areas
  • Investigate the concept of conservation of energy in fluid systems
  • Study the effects of varying outlet area (A2) on flow dynamics
USEFUL FOR

Students studying physics, particularly those focusing on fluid dynamics and energy conservation, as well as educators looking for practical examples of kinetic energy calculations in fluid systems.

byahnoob
Messages
1
Reaction score
0

Homework Statement



A block of mass m is connected to a massless rod and plunger of area A1 on a cylindric container of water. At

the bottom of the container there is a pipe that leads to an opening of area A2 where the water pours out at a

velocity v. The block starts at rest with the plunger a distance h from the bottom of the container.

A] What pressure does the block apply to the water? Only use A1 , m, and g in your answer.

B] What kinetic energy does the block have as water pours from the opening? Express your answer in terms of m, g, A1 , A2 , P0 , h, and ρ .

HINT* - solving for 1⁄2 v2 will get you very close to an expression for K.

[ATTACHED PICTURE OF PROBLEM]

Homework Equations



F = PA
Bernoulli's equation
KE = 1/2mv^2

The Attempt at a Solution


A] F = PA
mg = PA1

answer:
mg/A1 = P

B] Using Bernoulli's equation
P + pgh = P0 + 1/2pv^2
mg/A1 + pgh = P0 + 1/2pv^2

REARRANGE

(1/p)(mg/A1 + pgh + P0) = 1/2v^2

answer:
KE = 1/2mv^2 = (m/p)(mg/A1 + pgh + P0)
AM I CORRECT OR WRONG? I don't know how to get that A2 to the answer of part B
 

Attachments

  • Screen Shot 2014-12-07 at 7.56.28 PM.png
    Screen Shot 2014-12-07 at 7.56.28 PM.png
    3.9 KB · Views: 501
Physics news on Phys.org
There are two velocities here, which you need separate variables for: the velocity of the water from the outlet (the given v), and the velocity of the mass (for which you need another symbol) . There is a relationship between them.
 

Similar threads

Replies
13
Views
2K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 7 ·
Replies
7
Views
1K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
24
Views
4K
Replies
2
Views
7K
  • · Replies 21 ·
Replies
21
Views
21K
  • · Replies 17 ·
Replies
17
Views
2K
Replies
14
Views
3K