Need help with a pressure/projectile motion problem

[panchoman]

Homework Statement

Here is the problem, from mastering physics:

Given description:
Suppose the opening in the tank of the figure is a height y1 above the base and the liquid surface is a height y2 above the base. The tank rests on level ground.

Question 1: At what horizontal distance from the base of the tank will the fluid strike the ground? Assume v2=0

I got the answer to this one, isolating v by using bernoulli's equation, getting that v=
sqrt(2g(y2-y1)

Then, using this velocity in the kinematics equations for the projectile getting that x = 2sqrt((y2-y1)y1)

visual of that:

Question 2:
At what other height, y'1, can a hole be placed so that the emerging liquid will have the same "range"?

Homework Equations

Bernoulli's equation (P1+.5pv^2+pgh=P2+.5pv^2+pgh)

Where P is pressure, and p is Ro, the density constant of the fluid.

The Attempt at a Solution

I went hunting for the explanation/solution of part b, but i couldn't really figure it out. everything i got, was wrong, and now i have 6 attempts remaining. Can someone explain how to arrive at the answer?

Many thanks,
Panchoman

 

[Mindscrape]

Basically there is a trade off. The higher up you go the less velocity the water spills out with. On the other hand, the higher up you go the more time the water has to travel before it hits the ground. You really just need to reverse the whole process of what you did in part 1.