Pressure exerted in an elevator

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    Elevator Pressure
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SUMMARY

The discussion focuses on calculating the pressure exerted by a suitcase in an upward-moving elevator. Given a suitcase mass of 16 kg and an elevator acceleration of 1.5 m/s², the normal force is calculated using the formula Fnormal = m(a + g), where g is the acceleration due to gravity (9.8 m/s²). The area of the suitcase in contact with the floor is 0.50 m by 0.15 m. The pressure in excess of atmospheric pressure can be determined by dividing the normal force by the contact area.

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A suitcase (mass m=16kg) is resting on the floor of an elevator. The part of the suitcase in contact with the floor measures 0.50m by 0.15m. The elevator is moving upward, the magnitude of its acceleration being 1.5m/s^2. What pressure (in excess of atmospheric pressure) is applied to the floor beneath the suitcase?

This problem isn't too hard. Elevator is going up so the pressure will be greater than normal produced by the suitcase. Take the area of the suitcase and continue from there?
 
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KingTutATL said:
A suitcase (mass m=16kg) is resting on the floor of an elevator. The part of the suitcase in contact with the floor measures 0.50m by 0.15m. The elevator is moving upward, the magnitude of its acceleration being 1.5m/s^2. What pressure (in excess of atmospheric pressure) is applied to the floor beneath the suitcase?

This problem isn't too hard. Elevator is going up so the pressure will be greater than normal produced by the suitcase. Take the area of the suitcase and continue from there?
What is the force exerted on the suitcase by the floor? What is the area over which this force acts? That should be all you need.

AM
 
When calculating the force do I just add 1.5m/s^2 to 9.8m/s^2 and then calculate the force per area from there?
 
KingTutATL said:
When calculating the force do I just add 1.5m/s^2 to 9.8m/s^2 and then calculate the force per area from there?
Conceptually, the acceleration and gravity are different. You would add the force of gravity (weight) which the floor applies with no acceleration, to the force which the elevetor applies to accelerate the suitcase:

F_{normal} = ma + mg

AM
 
Of course, that's just
F_{normal}= m(a+ g)
as KingTutAtl asked.
 
HallsofIvy said:
Of course, that's just
F_{normal}= m(a+ g)
as KingTutAtl asked.
Of course. I should have begun my answer with: "Yes, provided you multiply by the mass". It appeared to me that the op was uncertain as to why you would add them together, since there is no acceleration due to gravity.

AM
 
Last edited:

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