B Pressure in a viscous liquid versus non-viscous fluids

AI Thread Summary
The discussion focuses on the definition of fluid pressure as outlined in H.C. Verma's "Concepts of Physics," emphasizing that this definition applies specifically to homogeneous, non-viscous fluids. The author highlights that for viscous fluids, pressure does depend on the orientation of the surface area due to the presence of shear stresses. The conversation also touches on the constitutive equation for Newtonian fluids, which relates viscosity, pressure, and velocity gradients, forming the foundation of fluid dynamics. This equation accounts for both shear and normal stresses, simplifying to an isotropic stress tensor under static conditions. The reference to "Transport Phenomena" by Bird et al. is suggested for further study on the topic.
Kashmir
Messages
466
Reaction score
74
Hc verma, concepts of Physics, vol 1 pg 258
"We define pressure of fluid at the point A as : ##P= F/\Delta S##
For a homogeneous and non-viscous fluid, this quantity does not depend on orientation of ##\Delta S## and hence we talk of pressure at a point".

Why did the author stress that the definition holds only for non-viscous fluids?
What happens to viscous fluids? Does the pressure depend on orientation in viscous fluids ?
 
Last edited by a moderator:
Physics news on Phys.org
Are you familiar with with the constitutive equation (rheological equation of state) for a Newtonian fluid in 3D in terms of the fluid viscosity, "pressure," and velocity gradient tensor? This is the more general version of Newton's law of viscosity that we learned about in freshman physics, and forms the basis of most of the fluid dynamics that we work with in practice. It includes not only shear stresses, but normal stress as well. The Newtonian fluid model reduces to an isotropic stress tensor (pressure) in the limit of static equilibrium.
 
Last edited:
Chestermiller said:
Are you familiar with with the constitutive equation (rheological equation of state) for a Newtonian fluid in 3D in terms of the fluid viscosity, "pressure," and velocity gradient tensor? This is the more general version of Newton's law of viscosity that we learned about in freshman physics, and forms the basis of most of the fluid dynamics that we work with in practice. It includes not only shear stresses, but normal stress as well. The Newtonian fluid model reduces to an isotropic stress tensor (pressure) in the limit of static equilibrium.
Thank you.
No, I've not studied it.
 
Kashmir said:
Thank you.
No, I've not studied it.
See Transport Phenomena by Bird et al
 
Consider an extremely long and perfectly calibrated scale. A car with a mass of 1000 kg is placed on it, and the scale registers this weight accurately. Now, suppose the car begins to move, reaching very high speeds. Neglecting air resistance and rolling friction, if the car attains, for example, a velocity of 500 km/h, will the scale still indicate a weight corresponding to 1000 kg, or will the measured value decrease as a result of the motion? In a second scenario, imagine a person with a...
Thread 'Gauss' law seems to imply instantaneous electric field propagation'
Imagine a charged sphere at the origin connected through an open switch to a vertical grounded wire. We wish to find an expression for the horizontal component of the electric field at a distance ##\mathbf{r}## from the sphere as it discharges. By using the Lorenz gauge condition: $$\nabla \cdot \mathbf{A} + \frac{1}{c^2}\frac{\partial \phi}{\partial t}=0\tag{1}$$ we find the following retarded solutions to the Maxwell equations If we assume that...
Dear all, in an encounter of an infamous claim by Gerlich and Tscheuschner that the Greenhouse effect is inconsistent with the 2nd law of thermodynamics I came to a simple thought experiment which I wanted to share with you to check my understanding and brush up my knowledge. The thought experiment I tried to calculate through is as follows. I have a sphere (1) with radius ##r##, acting like a black body at a temperature of exactly ##T_1 = 500 K##. With Stefan-Boltzmann you can calculate...
Back
Top