Calculating Pressure Change in Liquid After Adding Weight

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    Liquid Pressure
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SUMMARY

The discussion centers on calculating the pressure change in a liquid after an object, specifically an aluminum ball, is introduced into a cup of water. The key equation referenced is p = ρgh, where ρ represents the density of the liquid, g is the acceleration due to gravity, and h is the height of the liquid column. When the ball is added, the water level rises, resulting in an increase in pressure at the bottom of the cup due to the increased height of the water column. The initial conclusion is confirmed that the pressure at the bottom increases as the depth of the water increases.

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mr.book
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This started to bother me today. In the first picture, there's a cup wheres a certain amount of water in it. A ball made of aluminium hasnt been dropped in the cup yet.
In the second picture, the ball has been dropped in.

The ball has not sinked, a string is holding it.

Now please tell me, how did the pressure on the botton of the cup created BY THE WATER change?
I mean, the water level just rose. So the pressure should also.
But there seems to be another solution to the problem, and I just can't figure it out.

The equation for liquid pressure is p= RO*g*h.

Thanks in advance,






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Your initial solution is correct. Since the depth of the water is now larger, the pressure at the bottom is higher.
 

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