Chemistry Pressure of gasoline in a closed container

AI Thread Summary
To determine the evaporation of gasoline in a closed container, one must consider the saturated vapor pressure of gasoline and its components at a specific temperature. The evaporation will continue until the vapor pressure reaches a critical point where the rate of evaporation equals the rate of condensation. Accurate calculations require access to tables of saturated vapor pressure for gasoline at 25°C. Since gasoline is a mixture of hydrocarbons, its composition can vary, complicating the determination of exact evaporation rates. Understanding these principles is essential for calculating the partial pressure of gasoline in a closed system.
barryj
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Homework Statement
A small amount of gasoline is placed in a 1 liter container along with the normal atmospheric pressure of 760 torr at 25C. Much but not all of the gasoline evaporates creating an increased pressure inside the container. At equilibrium, what will be the total pressure in the container?
Relevant Equations
pv = nrt P total = P atmosphere + P gasoline
If I knew how much of the gasoline evaporated, then I could use p = nRT/V to fine the partial pressure of the gasoline and add it to the pressure of the atmosphere. So my question is, How do I find how much of the gasoline will evaporate. I would think that the gasoline would evaporate until it reached some critical pressure at which time the evaporation rate would equal the disolving rate. but how do I find this? Is there some law I do not know about?
 
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Gasoline is a mixture of hydrocarbons, and it doesn't have a definite composition - so it is not like there is an unambiguous answer to the question.

There is not much you can do without tables of saturated vapor pressure of gasoline (or it most typical components) at 25°C.
 
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