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2. Homework Equations

**P = P(atmosphere) + ρ*g*h**

3. I tried finding the pressure on the window, using P = F/A and got the maximum pressure the submarine window can handle as P = 10^6/(pi*(0.1)^2) = 3.18*10^7 Pa.

I then used P = P(atmosphere) + ρ*g*h

and substitued, P as 3.18*10^7, P(atmosphere) as 101,300, ρ(used density of seawater) as 1030, g as 9.8 and found h to be approximately 3140m.

The solutions found h to be 3153m.

I don't know where I have gone wrong...