Pressure on uniformly charge spherical shell

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Homework Help Overview

The problem involves calculating the pressure exerted on a uniformly charged spherical shell due to the charges on its surface. The context includes understanding electric fields and energy stored in electric fields related to electrostatics.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to use the principle of virtual work to derive the pressure, integrating the energy stored in the electric field. Some participants suggest a simpler formula for electrostatic pressure, while others question the application of the principle of virtual work.

Discussion Status

Participants are exploring different methods to calculate the pressure, with some providing alternative formulas and others verifying the original poster's approach. There is acknowledgment of a potential error in the original poster's calculations, but no consensus has been reached on the correct method.

Contextual Notes

There is a mention of a possible typographical error in the original poster's equation, indicating a need for careful verification of the derived expressions.

timhunderwood
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Homework Statement



First part of the problem was to work out E-field of uniformly charged spherical shell with charge Q and Radius R.

This was fine : E = 0 for r<R
and E = Q/(4*Pi*eps*r2) for r>R

QUESTION:
Find the pressure exerted on the shell due to the charges on its surface.

Homework Equations


The Attempt at a Solution



I tried to do it using the principle of virtual work, I get an answer and was hoping someone could confirm it is right?

I did this:
u_s, Energy stored in Electric field = [tex]\int[/tex]eps*E2/2 (integrate over all space)

I did this in spherical polar coordinates and get U_s = Q2/(8*Pi*eps*R)

I then said (principle of virtual work:)

F, Force*dR = [tex]\partial[/tex]U_s/[tex]\partial[/tex]R *dR
and solved this to get:
F = -Q2/(8*Pi*eps*R2)

dividing by area of shell then gives

pressure = Q2/(32*Pi2*eps*R2)

is this right? If there's a mistake I think I may have not used the principle of virtual work correctly...

Thanks very much.
 
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I do believe you are making this a little more complicated than necessary. The electrostatic pressure on the surface is given by the formula

[tex]P=\frac{\varepsilon_0}{2}E^2[/tex]

(cf. Griffiths Equation 2.52)
 
timhunderwood said:
pressure = Q2/(32*Pi2*eps*R2)

is this right? If there's a mistake I think I may have not used the principle of virtual work correctly...
You're missing a factor of R^2 in the denominator, but otherwise, yes, that is fine.
 
Thats good,

I mistyped my last equation- it should have read R^4.

Thanks for the help
 

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