- #1
erkokite
- 39
- 0
Hello,
I am fairly new to quantum physics (I'm actually an engineer, not a physicist). I think I am getting a decent grasp on things, but I have a question.
Suppose you have two time dependent states: [tex]\Psi_{1}[/tex] and [tex]\Psi_{2}[/tex].
Also, suppose that we have a constant potential, represented in our Hamiltonian as V.
Our Hamiltonian is thus represented as: [tex]\hat{H}=1/(2m)\partial^2/x^2+V(x)[/tex]
Now suppose that we want to find the probability amplitude to go from state 1 to the 2nd state in a time interval t1 to t2.
It is my understanding that the following operation is used:
[tex]<\Psi_{2}|exp(-i\hat{H}(t2-t1))|\Psi_{1}>[/tex]
This is of course equal to
[tex]\int\Psi_{2}*exp(-i\hat{H}(t2-t1))\Psi_{1}dx[/tex]
However, how do I evaluate the following operation?
[tex]exp(\hat{H})\Psi_{1}[/tex]
Many thanks.
I am fairly new to quantum physics (I'm actually an engineer, not a physicist). I think I am getting a decent grasp on things, but I have a question.
Suppose you have two time dependent states: [tex]\Psi_{1}[/tex] and [tex]\Psi_{2}[/tex].
Also, suppose that we have a constant potential, represented in our Hamiltonian as V.
Our Hamiltonian is thus represented as: [tex]\hat{H}=1/(2m)\partial^2/x^2+V(x)[/tex]
Now suppose that we want to find the probability amplitude to go from state 1 to the 2nd state in a time interval t1 to t2.
It is my understanding that the following operation is used:
[tex]<\Psi_{2}|exp(-i\hat{H}(t2-t1))|\Psi_{1}>[/tex]
This is of course equal to
[tex]\int\Psi_{2}*exp(-i\hat{H}(t2-t1))\Psi_{1}dx[/tex]
However, how do I evaluate the following operation?
[tex]exp(\hat{H})\Psi_{1}[/tex]
Many thanks.