Probability density for related variables

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SUMMARY

The discussion focuses on calculating the probability density of magnetization (M) in a system of spins, where the probability density of m spins up is defined as ##\omega_m(m)=\frac{1}{2^N}\frac{N!}{m!(N-m)!}##. The user proposes substituting m with (M+N)/2 to express the probability density in terms of M. This approach is validated, but the importance of considering parity in the calculations is emphasized as a critical factor in determining the accuracy of the results.

PREREQUISITES
  • Understanding of statistical mechanics and spin systems
  • Familiarity with probability density functions
  • Knowledge of combinatorial mathematics, specifically binomial coefficients
  • Basic grasp of magnetization concepts in physics
NEXT STEPS
  • Study the implications of parity in statistical mechanics
  • Explore advanced topics in probability density functions
  • Research the relationship between magnetization and spin configurations
  • Learn about the applications of binomial distributions in physical systems
USEFUL FOR

Students and researchers in physics, particularly those focusing on statistical mechanics, magnetism, and probability theory. This discussion is beneficial for anyone looking to deepen their understanding of probability densities in spin systems.

diegzumillo
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Homework Statement


Say I calculated a probability density of a system containing m spins up (N is the total number of particles). The probabilities of being up and down are equal so this is easy to calculate. Let's call it ##\omega_m##. Then we define magnetization as ##M=2m-N## and it asks me to calculate the probability density of M.

Homework Equations


##\omega_m(m)=\frac{1}{2^N}\frac{N!}{m!(N-m)!}##

The Attempt at a Solution


I'm not sure how to interpret a probability density of M. M can have a value between -N and N, so the probability, for example, of M=-N is the same as m=0. This suggests me that I can simply replace m for (M+N)/2 in its probability density expression. I don't know if that makes sense, the mathematical properties of these probability densities are no where to be found (at least not with this particular detail).
 
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I think my comprehensioon of that probability density improved a bit. It's the probability of the system to be in the state defined by N and m (or M), so my solution obtained from simply rewriting ##\omega## as ##\omega(N,M)## is right. Right?
 
diegzumillo said:
This suggests me that I can simply replace m for (M+N)/2 in its probability density expression.
Yes, except consider parity.
 

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