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## Main Question or Discussion Point

given that x has an exponential density function ie p(x) = exp (-x) and x(n) & x(m) are statistically independent.

Now y(n) = x(n-1)+x(n)

what is the pdf (probability density function) of y(n)

Now y(n) = x(n-1)+x(n)

what is the pdf (probability density function) of y(n)