Probability dependence on potential

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Homework Help Overview

The discussion revolves around the relationship between potential energy and probability density in quantum mechanics, particularly in the context of the Schrödinger equation. Participants explore how variations in potential energy (V) affect the behavior of wave functions (ψ) and their associated probabilities.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the implications of energy levels (E) relative to potential (V) and how this affects wave function characteristics, such as amplitude and frequency. Questions arise about the interpretation of probability densities and their relation to given potentials.

Discussion Status

The conversation is active with various interpretations being explored. Some participants offer insights into specific cases, while others seek clarification on the nature of the problem and the options provided in the homework statement. There is an ongoing examination of the assumptions underlying the problem.

Contextual Notes

Participants note the lack of information regarding particle energy in the homework statement, which adds complexity to the analysis of the potential graph and the corresponding probability densities.

Kaguro
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Homework Statement
Say, I am given a random looking graph of potential V(x) vs x. I'm not given any information about particle energy. The question then asks me to choose the correct option of ##|\psi (x)|^2##. I feel like the probability density should be higher where potential is lower. But why exactly should that be?
Relevant Equations
I don't know...
I only know that if E>V, then the frequency would be higher where E-V is higher. But what does that have anything to do with probability?
 
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Shrodinger equation is written as
[tex][(\frac{d}{dx})^2+\frac{(E-V)2m}{\hbar^2}]\psi=0[/tex]
Depending on sign of E-V ##\psi## does sinusoidal vibration or exponential dumping.
 
Yes, I know. I wanted to ask if V is relatively lower at an x, would that imply that the amplitude will be relatively higher?
 
In order to check your hypothesis why do not you review the cases you well know, e.g. V(x) = kx^2, V(x)=0 for -a<x<a, V otherwise, not only ground state but also excited states ?
 
For Harmonic oscillator, the ground state is fine. But in the excited states, we can see a piling away from centre.

In the finite square well, if E>V, then the amplitude doesn't change, but frequency decreases in the regions |x|>a.

If E<V, then it shows an exponentially decaying amplitude.

If there's a block of V, then after exponentially decaying, it again becomes simple harmonic with reduced amplitude.
 
Your consideration seems reasonable to me, though I am not confident in catching your teacher's intention.
 
Kaguro said:
Homework Statement:: Say, I am given a random looking graph of potential V(x) vs x. I'm not given any information about particle energy. The question then asks me to choose the correct option of ##|\psi (x)|^2##.
What do you mean by "choose the correct option"? Are you given a certain number of options and are asked to pick one or more? If so, what are they?
 
The potential is like this:
potential.png

The probability densities are like this:

wave.png


Something like this. c and d are useless. a and b.

a is similar to the potential given. b is the opposite.
 
Probability densities are square integrable. Is that the case with all the choices? Hint: No.

Of the ones that are square integrable, which one looks like the best candidate given that your potential looks like it does?

Also, don't expect the probability density to be similar to the potential, whatever that means.
 

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