Probability Formula Help: Finding P(B|A) with Given Probabilities

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Homework Help Overview

The discussion revolves around calculating the conditional probability P(B|A) given certain probabilities: P(A) = 0.7, P(B) = 0.5, and P([A U B]') = 0.1. Participants are exploring the relationships between these probabilities to find P(B|A).

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the formula for conditional probability and express uncertainty about how to find P(B intersection A). There is a suggestion to use the formula for P(A U B) to relate it to P(A intersection B). Questions arise about how to derive P(A U B) from the given information.

Discussion Status

The discussion is active, with participants sharing insights about relevant probability formulas. Some guidance has been offered regarding the relationships between the probabilities, but there is no explicit consensus on the next steps or final outcomes.

Contextual Notes

Participants are working within the constraints of the given probabilities and are attempting to derive additional values needed to solve for P(B|A). There is an acknowledgment of the need to find P(B U A) and P(A intersection B) based on the provided information.

mutzy188
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Homework Statement



P(A) = .7
P(B) = .5
P( [A U B]' ) = .1

Find: P(B|A)

The answer is 3/7


Homework Equations



P(B|A) = [P(B intersection A)] / [P(B)]

The Attempt at a Solution



I know the formula:

P(B|A) = [P(B intersection A)] / [P(B)]

but how do I find P(B intersection A)] ?

any help would be greatly appreciated.

Thanks
 
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Is there a formula for [itex]P(A \cup B)[/itex] that has [itex]P(A \cap B)[/itex] in it?
 
Yeah,


P(A U B) = P(A) + P(B) - P(A intersect B)
 
That's the one. Now how can you find P(A U B) with the information you are given?
 
i don't know. Thats what i got stuck on
 
I need P(B intersect A)

P(B intersect A) = P(A) + P(B) - P(B U A)


but i don't know how to find P(B U A)
 
If you knew P(X') could you find P(X)?
 
Yeah,

P(X') = 1 - P(X)
 
And you are given that P([A U B]') = .1, so what is P([A U B])? Now what is P(A intersect B), and finally what is P(B|A)?

edit... You wrote the formula for P(B|A) incorrect. It should be [tex]P(B|A) = \dfrac{P(A\cap B)}{P(A)}[/tex].
 
Last edited:

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