Probability/Moment Generating Function

Click For Summary
SUMMARY

The discussion focuses on the transformation of a normally distributed random variable X ~ Normal(μ,σ²) into Y = e^X. The probability density function (PDF) of Y is derived using the change of variables technique, yielding fy(y) = (1/y)(1/√(2πσ²)e^(-(ln(y)-μ)²/(2σ²))). Furthermore, it is established that the moment generating function (MGF) of Y does not exist due to the divergence of the integral ψY(t) = E(e^(tY)) as y approaches +∞, necessitating an analysis of the behavior of the function e^(ty)fy(y).

PREREQUISITES
  • Understanding of Normal distribution and its properties
  • Knowledge of probability density functions (PDFs)
  • Familiarity with moment generating functions (MGFs)
  • Experience with integration techniques in probability theory
NEXT STEPS
  • Study the properties of the Normal distribution and transformations of random variables
  • Learn about the derivation and applications of moment generating functions
  • Explore advanced integration techniques for evaluating complex integrals
  • Investigate the behavior of functions at infinity in the context of probability
USEFUL FOR

Students and professionals in statistics, probability theory, and mathematical finance, particularly those dealing with transformations of random variables and moment generating functions.

tiger2030
Messages
22
Reaction score
0

Homework Statement


Let X ~ Normal(μ,σ2). Define Y=eX.
a) Find the PDF of Y.
b) Show that the moment generating function of Y doesn't exist.

Homework Equations

The Attempt at a Solution


For part a, I used the fact that fy(y) = |d/dy g-1(y)| fx(g-1(y)). Therefore I got that fy(y)= (1/y)(1/√(2piσ2)e-(ln(y)-μ)2/2σ2

Then for b), I used ψY(t)=E(etY)=∫etyfy(y)dy. When I plug in fy(y) I get a function that is nonlinear and too complicated to integrate. If someone could give me a hint on the next step it would be greatly appreciated.
 
Physics news on Phys.org
You need to analyze the behavior of ##e^{ty} f(y)## for ##y \to + \infty## in order to show that the integral does not converge. You do not need to actually compute the integral to do that.
 
Where do I start in showing that (1/y)ety-ln(y)2/(2σ2)+2μln(y)/(2σ2) does not converge?
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
3
Views
2K
Replies
6
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K